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never [62]
3 years ago
6

What is the following sum 4(^5√x^2y)+3(^5√x^2y)

Mathematics
2 answers:
satela [25.4K]3 years ago
8 0
I think it should be B but I’m probably wrong so risk it if you want sorry
lesya [120]3 years ago
3 0
Your correct answer would be C

Hope this helps!

Have a great day! :)

~Violet
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Verify by direct substitution that the given power series is a solution of the indicated differential equation. [Hint: For a pow
shepuryov [24]

Answer:

The given power series y =\sum^{\infty}_{n=0} {(-1)^n x^{2n}} is a solution of the differential equation (1+x^2)y' + 2xy = 0

Step-by-step explanation:

This is a very trivial exercise, follow the steps below for the solution:

Step 1: Since n = 0, 1, 2, 3, 4, ........, Substitute the values of n into equation (1) below.

y =\sum^{\infty}_{n=0} {(-1)^n x^{2n}}.....................(1)

y = 1 - x^2 + x^4 - x^6 + x^8.........

Step 2: Find the derivative of y, i.e. y'

y' = -2x + 4x^3 - 6x^5 + 8x^7 .............

Step 3: Substitute y and y' into equation (2) below:

(1+x^2)y' + 2xy = 0\\\\(1+x^2)(-2x + 4x^3 - 6x^5 + 8x^7......) + 2x(1 - x^2 + x^4 - x^6 + x^8.......) = 0\\\\-2x+ 4x^3 - 6x^5 + 8x^7........ - 2x^3 +4x^5 - 6x^7 + 8x^9 ......+ 2x - 2x^3 + 2x^5 - 2x^7 + 2x^9...... = 0\\\\0 = 0

(Verified)

Since the LHS = RHS = 0, the given power series y =\sum^{\infty}_{n=0} {(-1)^n x^{2n}} is a solution of the differential equation (1+x^2)y' + 2xy = 0

6 0
3 years ago
can the locus of the points idea can be used to define straight lines,cicles,and even more complex shapes such as parables
Ulleksa [173]
<span>The answer would be True not false.</span>
7 0
3 years ago
The equation of a line in this form y - y1 = m ( x - x1) is called the ____-_____form.
loris [4]

Answer:

The equation of a line in this form y- y1=m (x - x1) is called the point slope form.

6 0
3 years ago
Multiple Choice
mihalych1998 [28]

Answer:

D is correct

Step-by-step explanation:

A graph of that sort will make a perfectly mirrored "V" shape, and with no offset, the bottom point will be on the y axis.  This means that the first equation will intercept the y axis at zero, the second will intercept the y-axis at -15.

"A" may seem correct also, as the second graph will intercept the x-axis at -15, but it is not complete, as it will intercept that axis at +15 as well.

7 0
2 years ago
Find the slope of the line that passes through (9, 6) and (4, 5).
boyakko [2]

Answer:

slope = \frac{1}{5}

Step-by-step explanation:

calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (9, 6 ) and (x₂, y₂ ) = (4, 5 )

m = \frac{5-6}{4-9} = \frac{-1}{-5} = \frac{1}{5}

8 0
2 years ago
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