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ddd [48]
3 years ago
15

Please help me with my problem

Mathematics
1 answer:
Doss [256]3 years ago
8 0
D and F are not equivalent to ax+bx+ac+bc+
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7+3 to the second power+(12-8) divided by 2x 4 is
cupoosta [38]

\bf \stackrel{\mathbb{P~E~M~D~A~S}}{7+3^2+(12-8)\div 2\times 4}\implies 7+3^2+(\stackrel{\downarrow }{4})\div 2\times 4\implies 7+\stackrel{\downarrow }{9}+(4)\div 2\times 4 \\\\\\ 7+9+\stackrel{\downarrow }{2}\times 4\implies 7+9+\stackrel{\downarrow }{8}\implies \stackrel{\downarrow }{16}+8\implies 24

5 0
3 years ago
Please help
ioda

Answer:

im 12!! how do you do this

Step-by-step explanation:

3 0
3 years ago
Question in the image
Komok [63]

Answer:

0.4

Step-by-step explanation:

consider this like some lines overlapping each other.

one line (A) is 0.5 long, the other (B) 0.4 long.

together they are 0.8 long.

that means that they overlap at a length of 0.1 (they share a segment 0.1 long).

of the combined line of 0.8 that has 0.1 of a joined segment, the complimentary part of B is therefore 0.4 (0.8 minus the original length of B).

8 0
3 years ago
325 people were in a tout group. Six buses were completely filled and 7 people chose to walk. How many people did the bus hold?
eduard
Remove these 7 guys from your number
so people who took buses are 318
now divide 318/6 to know how many phone did each bus have
5 0
3 years ago
Consider the following set of equations, where s, s0, x and r have units of length, t has units of time, v has units of velocity
Anna11 [10]

Answer:

5

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is \frac{LT^{-2}}{LT^{-1}}

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

8 0
3 years ago
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