Answer:
Hello Sir/ Mam
YOUR REQUIRED ANSWER IS 18.6%
Variables defined in the question:
H - Home - Games
W - Winning Games
Now, given:
P(H0.62 PW)0.22
P(W\mid H)=0.30
Required : Of all the games, percentage of games that were at home wins.
Hence, required :
P(W\cap H)
Now, we know that:
P(W\mid H)=\frac{P(W\cap H)}{P(H)}
0.3=\frac{P(W\cap H)}{0.62}
Hence,
P(W\cap H)=0.3*0.62=0.186=18.6\%
I hope this solves your doubt.
Feel free to comment if you still have any query.
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Step-by-step explanation:
Answer:
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Step-by-step explanation:
We formulate null and alternate hypotheses are
H0 : u1 < u2 against Ha: u1 ≥ u 2
Where u1 is the group tested after they were awake for 24 hours.
The Significance level alpha is chosen to be ∝ = 0.05
The critical region t ≥ t (0.05, 13) = 1.77
Degrees of freedom is calculated df = υ= n1+n2- 2= 5+10-2= 13
Here the difference between the sample means is x`1- x`2= 35-24= 11
The pooled estimate for the common variance σ² is
Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]
= 1/13 [ 120²+360²]
Sp = 105.25
The test statistic is
t = (x`1- x` ) /. Sp √1/n1 + 1/n2
t= 11/ 105.25 √1/5+ 1/10
t= 11/57.65
t= 0.1908
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
When it is in () it means multiply x=45
.4 is your answer....................
Answer: 8 m/s
First let’s convert the time to seconds. There are 69 seconds in a minute so 1 minute and 40 seconds is 60 +40 second which totals to 100 seconds
Now to get the speed in meters per second we divide the total meters run by the total seconds
So the speed will be 800m/100s = 8m/s
