4 years ago

Math homeworkkkkkkkkkkkk

Mathematics

1 answer:

Blababa [14]4 years ago

6 0

Hopefully these are correct lol, make sure to check it with a classmate. but i tried :)

You might be interested in

What is the answer to this

guapka [62]

Alright, first blank one is 1/3, then 2/3, then 1, then 1 1/3, then 1 2/3.
Now, shade the 1/3 and 2/3 in blue. Shade the 0, 1 and 2 in red.
Shade the 1 1/3 and 1 2/3 in yellow.
Glad I could help, and good luck!

7 0

3 years ago

Read 2 more answers

Which of the following id the graph of y= -2•3^5-x

Olin [163]

Answer:

Can you put the graph in

Step-by-step explanation:

5 0

3 years ago

What’s the answer to this

8090 [49]

1. 30/120

2. 30/100

Have a gold day:)

6 0

3 years ago

Differentiating Functions of Other Bases In Exercise, find the derivative of the function.

aniked [119]

Answer:

$\dfrac{dy}{dx} = \frac{2x-3}{\ln 16(x^2 - 3x)}$

Step-by-step explanation:

We are given the following in the question:

$y = \ln {16}(x^2 - 3x)$

We have to find the derivative of the given expression.

$y = \ln 16(x^2 - 3x)\\\text{Using the log propert}\\\\\log_a b = \dfrac{\log b}{\log a}\\\\dfrac{d(x^n)}{dx} = nx^{n-1}\\\\\dfrac{d(\log x)}{dx} = \dfrac{1}{x}\\\\\text{\bold{Differentiating we get}}\\\\\displaystyle\frac{dy}{dx} = \frac{d(\ln 16(x^2-3x))}{dx}\\\\= \frac{1}{16(x^2-3x)})\frac{d(x^2-3x)}{dx}\\\\=\frac{1}{\log 16(x^2-3x)}(2x - 3)\\\\= \frac{2x-3}{\ln 16(x^2 - 3x)}$

$\dfrac{dy}{dx} = \frac{2x-3}{\ln 16(x^2 - 3x)}$

7 0

4 years ago

12,000,055 + 60 + 16 + 90 x 40

Naddika [18.5K]

Answer: 12003731

Step-by-step explanation: Hope this helps

7 0

3 years ago

Read 2 more answers