Answer:
|7| - 7 = 0
2|-7| = 14
(-7)^2 = 49
-7-|-7|= -14
-7-1-71= -79
Step-by-step explanation:
Answer:
x = - 8 , x = 2
Step-by-step explanation:
the absolute value function always gives a positive result, however, the expression inside can be positive or negative, , that is
x + 3 = 5 ( subtract 2 from both sides )
x = 2
or
-(3 + x) = 5
- 3 - x = 5 ( add 3 to both sides )
- x = 8 ( multiply both sides by - 1 )
x = - 8
Answer:
a_n = 2.2 + 0.6 n
a_50 = 32.2
Step-by-step explanation:
What's the common difference of this series?
![a_1 = 2.8](https://tex.z-dn.net/?f=a_1%20%3D%202.8)
![a_2 = 3.4](https://tex.z-dn.net/?f=a_2%20%3D%203.4)
Common difference =
.
Expression for the nth term:
![a_n = a_1 + (n - 1) \cdot\text{Common Difference} \\\phantom{a_n } = 2.8 + 0.6 \; (n-1) \\\phantom{a_n} = 2.8 + 0.6 \; n - 0.6\\\phantom{a_n} = 2.2 + 0.6\; n](https://tex.z-dn.net/?f=a_n%20%3D%20a_1%20%2B%20%28n%20-%201%29%20%5Ccdot%5Ctext%7BCommon%20Difference%7D%20%5C%5C%5Cphantom%7Ba_n%20%7D%20%3D%202.8%20%2B%200.6%20%5C%3B%20%28n-1%29%20%5C%5C%5Cphantom%7Ba_n%7D%20%3D%202.8%20%2B%200.6%20%5C%3B%20n%20-%200.6%5C%5C%5Cphantom%7Ba_n%7D%20%3D%202.2%20%2B%200.6%5C%3B%20n)
n = 50 for the fiftieth term. Therefore
.
<h2>
Hello!</h2>
The answer is:
The correct option is the option D
![g=1.63\frac{m}{s^{2}}](https://tex.z-dn.net/?f=g%3D1.63%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
<h2>
Why?</h2>
To calculate the acceleration, we need to use the following formula that involves the given information (initial speed, final speed, and time).
We need to use the following free fall equation:
![V_{f}=V_{o}-g*t](https://tex.z-dn.net/?f=V_%7Bf%7D%3DV_%7Bo%7D-g%2At)
Where:
is the final speed.
is the initial speed.
g is the acceleration due to gravity.
t is the time.
We are given the following information:
![V_{f}=8.15\frac{m}{s}](https://tex.z-dn.net/?f=V_%7Bf%7D%3D8.15%5Cfrac%7Bm%7D%7Bs%7D)
![V_{o}=0\frac{m}{s}](https://tex.z-dn.net/?f=V_%7Bo%7D%3D0%5Cfrac%7Bm%7D%7Bs%7D)
![t=5seconds](https://tex.z-dn.net/?f=t%3D5seconds)
Then, using the formula to isolate the acceleration, we have:
![V_{f}=V_{o}-g*t](https://tex.z-dn.net/?f=V_%7Bf%7D%3DV_%7Bo%7D-g%2At)
![V_{f}=V_{o}-g*t\\\\g*t=V_{o}-V_{f}\\\\g=\frac{V_{o}-V_{f}}{t}](https://tex.z-dn.net/?f=V_%7Bf%7D%3DV_%7Bo%7D-g%2At%5C%5C%5C%5Cg%2At%3DV_%7Bo%7D-V_%7Bf%7D%5C%5C%5C%5Cg%3D%5Cfrac%7BV_%7Bo%7D-V_%7Bf%7D%7D%7Bt%7D)
Now, substituting we have:
![g=\frac{V_{o}-V_{f}}{t}](https://tex.z-dn.net/?f=g%3D%5Cfrac%7BV_%7Bo%7D-V_%7Bf%7D%7D%7Bt%7D)
![g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}](https://tex.z-dn.net/?f=g%3D%5Cfrac%7B0-8.15%5Cfrac%7Bm%7D%7Bs%7D%7D%7B5seconds%7D%3D-1.63%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
Therefore, since we are looking for a magnitude, we have that the obtained value will be positive, so:
![g=1.63\frac{m}{s^{2}}](https://tex.z-dn.net/?f=g%3D1.63%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
Hence, the correct option is the option D
![g=1.63\frac{m}{s^{2}}](https://tex.z-dn.net/?f=g%3D1.63%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
Have a nice day!
Answer:
23 %
Step-by-step explanation:
151.34 ÷ 658 × 100
hope this helps
have a nice day <3