![A= \frac{1}{2} h (x+y)](https://tex.z-dn.net/?f=%20A%3D%20%5Cfrac%7B1%7D%7B2%7D%20h%20%28x%2By%29%20)
we have to solve for x , solving for x means , we have to isolate x one one side , by shifting all other variables to other side
So
![A= \frac{1}{2} h (x+y)](https://tex.z-dn.net/?f=%20A%3D%20%5Cfrac%7B1%7D%7B2%7D%20h%20%28x%2By%29%20)
Multiply both sides by 2
2A = h(x+y)
Divide both sides by h
2A/h = x+y
Subtract y from both sides
![\frac{2A}{h} -y =x](https://tex.z-dn.net/?f=%20%5Cfrac%7B2A%7D%7Bh%7D%20%20-y%20%3Dx%20)
or
![x=\frac{2A}{h} -y](https://tex.z-dn.net/?f=%20x%3D%5Cfrac%7B2A%7D%7Bh%7D%20%20-y%20)
The answer for the first one would be 4 just divide both 16 & 4.
The answer for the second one would be -7 just divide both 63 & -9.
The answer for the third one would be -36 just multiply both 12 and -3.
The answer for the fourth one would be -120 just multiply -10 and 12.
Answer:
-9A · √(5yA)
Step-by-step explanation:
The coefficient -3 stays the same.
45 factors into 5·9, which is helpful because 9 is a perfect square.
Thus, √45 = 3√5.
y cannot be factored. It stays under the radical.
A³ can be factored into A² (a perfect square) and A.
Thus,
-3√(45yA³) = -3 · 3√5 · √y · A · √A, or
= (-3)(3)(A) · √(5yA), or
= -9A · √(5yA)
Answer:
Perimeter = 21.58 units
Step-by-step explanation:
Perimeter of a polygon = Sum of measures of all sides of the polygon
Perimeter of the quadrilateral LEAP = PL + AE + EL + LP
= 4.47 + 4.47 + 6.32 + 6.32
= 21.58 units
[If the distances between two point are not given, use the formula to calculate the distance between two points
and ![(x_2,y_2)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29)
Distance =
]
Acute angles because they are less then 90 degrees which is a right angle.