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Zepler [3.9K]
3 years ago
6

Write 16x^2 + 25y^2 - 32x -159 =0 In standard form

Mathematics
1 answer:
Irina18 [472]3 years ago
7 0
16x^2 + 25y^2 - 32x -159 =0:x 

Solve by using <span>Quadratic Formula

</span>x= \dfrac{-b+ \sqrt{b^2-4ac} }{2a}, \dfrac{-b- \sqrt{b^2-4ac} }{2a} 

In this case, a=16<span>,</span>b=-32<span> and </span>c=25{y}^{2}-159<span>

</span>x= \dfrac{32+ \sqrt{(32)^2-4*16(25y^2-159)} }{2*16} ,}\dfrac{32- \sqrt{(32)^2-4*16(25y^2-159)} }{2*16} 
<span>
</span>x= \dfrac{32+40i \sqrt{y^2-7} }{32} , \dfrac{32-40i \sqrt{y^2-7} }{32} 
<span>
</span>x=1+ \dfrac{5i \sqrt{y^2-7} }{4} ,1- \dfrac{5i \sqrt{y^2-7} }{4}<span>
</span>
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there are 10 less trumpet players than saxophone players. The number if saxophone players is 3 times the number of trumpet playe
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<em>Answer: There are 5 trumpet players and 15 saxophone player</em>


<em>Step-by-step explanation: Let a be the number of trumpet players </em>

<em>Let b be the number of saxophone players </em>

<em>--------------------- </em>

<em>(1) a = b-10 </em>

<em>(2) b =3a </em>

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<em>Substitute  </em>

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<em>There are 5 trumpet players and 15 saxophone player</em>


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3 years ago
After being rearranged and simplified, which of the following equations could be solved using the quadratic formula? Check all t
Naddika [18.5K]

Answer:

The options 2x² + x² + x = 30 and  9x + 3x² = 14 + x + 1, and -x² + 4x + 7 = - x² - 9

Step-by-step explanation:

After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?

The answers are:

2x² + x² + x = 30

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wolverine [178]

Answer:

a) The 99% confidence interval is interval B: 3.35 to 4.35

The 90% confidence interval is interval A: 3.55 to 4.15.

b) Check Explanation.

Step-by-step explanation:

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value is obtained from either the t-distribution or the z-distribution tables. It depends on sample size and for smaller sample sizes, whether there is information provided for the population mean and standard deviation.

But whether z-distribution or t-distribution, the critical value increases as the confidence level increases.

Hence, the critical value for the 99% confidence level will be higher than the critical value for the 90% confidence level.

And since all the other parameters that determine the confidence interval and it's width (sample mean and the standard error of the mean) are the same for the 90% and the 99% confidence interval, the larger critical value for the 99% confidence interval means that it has the bigger width.

Hence, of the two intervals given,

Interval A: 3.55 to 4.15

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The larger interval, (3.35, 4.35) is the 99% confidence interval and the smaller interval, (3.55, 4.15) is the 90% confidence interval.

b) The data required for this second part isn't available, but the answer for the confidence interval can be obtained using the steps I have given above and below.

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The sample mean and the standard error of the mean are obtained from the sample data (which is missing).

Sample mean = (Σx)/N

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N = number of variables = 20

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σ = standard deviation (obtained from the sample data)

90% critical value for sample size of 20 = 1.73

99% critical value for sample size of 20 = 2.86

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