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Zepler [3.9K]
3 years ago
6

Write 16x^2 + 25y^2 - 32x -159 =0 In standard form

Mathematics
1 answer:
Irina18 [472]3 years ago
7 0
16x^2 + 25y^2 - 32x -159 =0:x 

Solve by using <span>Quadratic Formula

</span>x= \dfrac{-b+ \sqrt{b^2-4ac} }{2a}, \dfrac{-b- \sqrt{b^2-4ac} }{2a} 

In this case, a=16<span>,</span>b=-32<span> and </span>c=25{y}^{2}-159<span>

</span>x= \dfrac{32+ \sqrt{(32)^2-4*16(25y^2-159)} }{2*16} ,}\dfrac{32- \sqrt{(32)^2-4*16(25y^2-159)} }{2*16} 
<span>
</span>x= \dfrac{32+40i \sqrt{y^2-7} }{32} , \dfrac{32-40i \sqrt{y^2-7} }{32} 
<span>
</span>x=1+ \dfrac{5i \sqrt{y^2-7} }{4} ,1- \dfrac{5i \sqrt{y^2-7} }{4}<span>
</span>
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