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bulgar [2K]
3 years ago
11

Sean is helping his dad build a tiled walkway in their backyard. The walkway will be 606060 feet long and 222 feet wide. The loc

al hardware store sells tiles which are 222 by 222 feet and come in boxes of 666.
How many boxes of tiles do they need?
Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
5 0
They will need 2730 boxes
irakobra [83]3 years ago
4 0
The answer would be 2730 boxes. Hope this helps. Let me know if u need help with anything else
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Evaluate the expression √(-6)/(√(-9) √(-1)) and write the result in the form a+bi.
DaniilM [7]
√6/3√i
Let me know if you need work

3 0
3 years ago
Solve the inequality. 18 > 12 + x
aleksley [76]
6>x take 12 from both sides
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An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $5900 and his st
Ghella [55]

Answer:

Step-by-step explanation:

Final Answer: 19.5%

4 0
3 years ago
PLEASE HELP THIS IS DUE TODAY
Neporo4naja [7]

The Mean Absolute Deviation is commonly known as MAD. The correct statement about the situation is D.

<h3>What is the Mean Absolute Deviation?</h3>

The Mean Absolute Deviation, commonly known as MAD is the average of the difference between the mean and the data points, it can also be referred to as the average of the deviations of the data points from the mean.

Given Two months ago, the mean daily rainfall in a local city was 9.4 cm. The mean absolute deviation was 3.5 cm. Last month, the mean daily rainfall in that city was 11.5 cm, and the mean absolute deviation was 1.6 cm.

As it is known that more MAD for data points means more deviation of the data points from the mean, while it is vice versa if it is less. Therefore, we can conclude Last month, the amount of rain that fell each day varied less than the month before.

Hence, the correct statement about the situation is D.

Learn more about the Mean Absolute Deviation:

https://brainly.in/question/8755707

#SPJ1

5 0
2 years ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
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