Answer:
A sample size of 128 is needed.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population(square root of the variance) and n is the size of the sample.
How large should a sample be if the margin of error is 1 minute for a 93% confidence interval
We need a sample size of n, which is found when . We have that . So
Rounding up
A sample size of 128 is needed.
Calculate Δ = b^2 -4ac => Δ = 169 => k1 = 3/2; k2 = -5 => 2k^2 + 7k - 15 = 2*(k -3/2)(k+5) = (2k - 3)(k+5);
Answer:
D)210 units ^2 I hope the answer is correct. I will be happy when I get 10 points
Answer: $1,624
Step-by-step explanation:
The amount after x-years is given as :
9 + 50x + 1000
Since x represents number of years , this means that after 6 years , the amount will be :
9( ) + 50(6) + 1000
⇒9(36) + 300 + 1000
⇒324 + 300 + 1000 =
Therefore, the amount after 6 years will be $1,624
6x+3y should be the answer