Answer:
+5
Step-by-step explanation:
Answer:
Step-by-step explanation:
The y-intercept cannot be (2,-8). The x-coordinate of the y-intercept is 0.
Point-slope equation for line of slope -5 that passes through (2,-8):
y+8 = -5(x-2)
Answer:
the line y = x intercept the unit circle x^2+y^2=1 at points:
(0.707, 0.707) and (-0.707, -0.707)
Step-by-step explanation:
The points of intersection are the points that satisfy the both following equations:
equation 1: y = x
equation 2: x^2 + y^2 = 1
So, we can replace equation 1 on equation 2 as following:
x^2 + y^2 = 1
As well y = x then:
x^2 + x^2 = 1
Isolating x we obtain:
2x^2=1
x^2 = 1/2
x=±0.707
Taking into account that the squared can be positive or negative, we have two solutions for x: x1=0.707 and x2=-0.707
Finally for find the value of y1 and y2, we replace the value of x1 and x2 on any of the principal equations (equation 1 or 2).
For simplicity we replace on Equation 1 (y = x), so:
y1=x1=0.707 and y2=x2=-0.707
Concluding that the line y = x intercept the unit circle x^2+y^2=1 at points:
(0.707, 0.707) and (-0.707, -0.707)
Answer:
Step-by-step explanation:
we know that
Area of a circle is equal to
A=pi* r^{2}
where
r is the radius
in this problem we have that
A=50 m^{2}
A=pi* r^{2} \\ r= \sqrt{A/pi} \\ r= \sqrt{50/pi}
r=4 m
we know that
the diameter is two times the radius
so
D=2r \\ D=2*4 \\ D=8 m