A)1.5 goals per match
b) 1.5x35= 52.5 so 53
Assuming she is consistent
Answer:
(4,1)
Step-by-step explanation:
let J(6,6) be x1, y1
let K(2,-4) be x2, y2
midpoint = (x1+x2)/2 , (y1+y2)/2
=(6+2)/2 ,(6-4)/2
= 8/2 ,2/2
=4, 1
Answer:
Step-by-step explanation:
Use math-way go quick and easy answers without step by step explanations, and use math-soup-calculator for step by step explanation
Using the Poisson distribution, there is a 0.8335 = 83.35% probability that 2 or fewer will be stolen.
<h3>What is the Poisson distribution?</h3>
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:
![P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20%5Cfrac%7Be%5E%7B-%5Cmu%7D%5Cmu%5E%7Bx%7D%7D%7B%28x%29%21%7D)
The parameters are:
- x is the number of successes
- e = 2.71828 is the Euler number
is the mean in the given interval.
The probability that a rental car will be stolen is 0.0004, hence, for 3500 cars, the mean is:
![\mu = 3500 \times 0.0004 = 1.4](https://tex.z-dn.net/?f=%5Cmu%20%3D%203500%20%5Ctimes%200.0004%20%3D%201.4)
The probability that 2 or fewer cars will be stolen is:
![P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)](https://tex.z-dn.net/?f=P%28X%20%5Cleq%202%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%2B%20P%28X%20%3D%202%29)
In which:
![P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20%5Cfrac%7Be%5E%7B-%5Cmu%7D%5Cmu%5E%7Bx%7D%7D%7B%28x%29%21%7D)
![P(X = 0) = \frac{e^{-1.4}1.4^{0}}{(0)!} = 0.2466](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20%5Cfrac%7Be%5E%7B-1.4%7D1.4%5E%7B0%7D%7D%7B%280%29%21%7D%20%3D%200.2466)
![P(X = 1) = \frac{e^{-1.4}1.4^{1}}{(1)!} = 0.3452](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20%5Cfrac%7Be%5E%7B-1.4%7D1.4%5E%7B1%7D%7D%7B%281%29%21%7D%20%3D%200.3452)
![P(X = 2) = \frac{e^{-1.4}1.4^{2}}{(2)!} = 0.2417](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%20%5Cfrac%7Be%5E%7B-1.4%7D1.4%5E%7B2%7D%7D%7B%282%29%21%7D%20%3D%200.2417)
Then:
![P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2466 + 0.3452 + 0.2417 = 0.8335](https://tex.z-dn.net/?f=P%28X%20%5Cleq%202%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%2B%20P%28X%20%3D%202%29%20%3D%200.2466%20%2B%200.3452%20%2B%200.2417%20%3D%200.8335)
0.8335 = 83.35% probability that 2 or fewer will be stolen.
More can be learned about the Poisson distribution at brainly.com/question/13971530
#SPJ1
Answer:
Option c. 104 people
Step-by-step explanation:
For 1 desk : 4 people
For 2 desks: 6 people
For 3 desks: 8 people
<em>For 51 desks: </em>
<em>We can see the pattern in the number of people that can be seated on the tables. </em>
Using arithmetic series: 4,6,8,....
a(n) = a1 + (n-1)d
n = 51
d = a2 - a1 = 6 - 4 = 2
a(51) = 4 + (51 - 1) 2
= 4 + (50)2
= 4 + 100
= 104