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3 years ago

Which number represents the value of the quotient below?

1 answer:

4 0

$\dfrac{5.0\cdot10^8}{2.0\cdot10^4}=\dfrac{5}{2}\cdot10^{8-4}=\boxed{2.5\cdot10^4}\\\\Used:\\\\\dfrac{a^n}{a^m}=a^{n-m}$

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dimaraw [331]

623. First find the volume of the rectangular prism, then find the volume of the cube. divide the volume area of the prism volume of the cube

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3 years ago

Anyone know the answer and the check to the equation 7 - 4c = 3c - 7 ?

Gelneren [198K]

Answer:

c=2

Step-by-step explanation:

7-4c=3c-7

7+7=3c+4c

14=7c

Dividing both sides by 7

c=2

CHECK:

Putting c in the above equation

7-4(2)=3(2)-7

7-8=6-7

-1=-1

Hence the above solution satisfies the given equation

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2 years ago

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Describe how you regroup when you find the sum of 64+43

Ivenika [448]

When adding two digit numbers u will be looking at the ones and deciding if they can regroup them for a ten. You might want to equate regrouping with trading a term that you will understand immediately you will begin to add 2 digit numbers by using ten and ones blocks. And the answer is (107)

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2 years ago

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Fifteen decreased by four times a number

expeople1 [14]

The answer is (4x)-15.

5 0

3 years ago

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Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

2 years ago