The answer is 12 because you got to add
The distance from point H to point J is 3 units.The value of n is 3.
Step-by-step explanation:
From the graph, point H is at (n,-6)
Point G location will be at (0,-6)
Point J is at (n,-3)
Observing point H(n,-6) and point J (n,-3) you notice that point J is above point H.find how much far is point H from point J.
d= √(x₂-x₁)²+(y₂-y₁)²
d=√(-3--6)²
d=√3² =√9 = 3
Distance H to J is 3 units
Point G (0,-6) and point H (n,-6) have a distance of 3 units same as point H to J
To get the horizontal length will ;
d=√ (n-0)²
d=√n² but d=3 units
3=√n²
9=n²
√9=n
3=n
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Distance between two points: brainly.com/question/1312275
Key terms : distance, point
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Answer:
c
Step-by-step explanation:
Answer:
AB = 13 units
Step-by-step explanation:
Calculate the distance d using the distance formula
d = 
with (x₁, y₁ ) = B(- 5, 12) and (x₂, y₂ ) = A (0, 0)
d = 
= 
= 
= 
= 13
Answer:
10,000
Step-by-step explanation:
"The number who have been vaccinated against both is twice the number who have been vaccinated only against mumps."
Let b = number of children vaccinated against both.
Let m = number of children vaccinated only against mumps.
b = 2m
"If 5,000 have been vaccinated against both"
5000 = 2m
m = 2500
5000 children are vaccinated against both.
2500 children are vaccinated only against mumps.
The total number vaccinated against mumps is the number vaccinated only against mumps plus the number vaccinated against both:
2500 + 5000 = 7500
"the number of children who have been vaccinated against rubella is twice the number who have been vaccinated against mumps."
total number of children vaccinated against rubella = 2 * 7500 = 15,000
5000 of those children are vaccinated against both.
15,000 - 5000 = 10,000
10,000 children are vaccinated only against rubella.
Answer: 10,000