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Svetllana [295]
3 years ago
9

7) A large candy bar was 147 calories. The smaller

Mathematics
2 answers:
stira [4]3 years ago
4 0

Answer:

The smaller candy bar is 95.55 calories

Step-by-step explanation:

Scorpion4ik [409]3 years ago
4 0

Answer:

papetushsidjdgfe just eheheie

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Solve the equation v^3=80
Luba_88 [7]

Answer:

4.31

Step-by-step explanation:

Find the cube root of both sides of the equation.

^3\sqrt{v^3} = ^3\sqrt{80}

The cube root will cancel out the cubed in the variable.

v = ^3\sqrt{80}

Find the cube root of 80. I rounded to the nearest hundredth.

v = 4.31

3 0
3 years ago
Read 2 more answers
What numbers multiply together to make 1120 but add to be -148
fenix001 [56]

Answer:

-140 and -8.

Step-by-step explanation:

  1. -140 x -8 = 1,120.
  2. -140 + -8 = -148.

These are all of the steps to completely and correctly solve this question.

Hope this helps!!!

Kyle.

8 0
3 years ago
Read 2 more answers
A plumber charges $50 for a service call plus $80 per hour. If she spends no longer than 8 hours a day at any one site, find a l
Paha777 [63]

Answer:

C(t)=80t+50, \text{ for }t\leq 8.

Step-by-step explanation:

Let C represent total daily charges in dollars and t represent time in hours.

We have been given that a plumber charges $50 for a service call plus $80 per hour.  

The amount charged for t hours would be 80t.

The total amount charged for t hours would be C(t)=80t+50.

We are also told that plumber spends no longer than 8 hours a day at any one site, this means that time t have a restriction as:

t\leq 8

Therefore, our required cost function would be C(t)=80t+50, \text{ for }t\leq 8.

3 0
4 years ago
HELP ME A INNOCENT CHILD PLEASSSSSSSSSSSE
agasfer [191]
1 YEAR = 12 months

divide: 5,031 ÷ 12 =  419.25

419 dollars and 25 cents each month

hope it helps!
4 0
4 years ago
Read 2 more answers
Elwin Osbourne, CIO at GFS, Inc., is studying employee use of GFS e-mail for non-business communications. A random sample of 200
ladessa [460]

Answer:

<em> The 90% confidence interval for the population proportion is</em>

<em>(0.10872, 0.19128)</em>

Step-by-step explanation:

<u><em>Explanation:</em></u>-

<u><em>Step(i)</em></u>:-

Given data A random sample of 200 e-mail messages was selected. Thirty of the messages were not business related

Given random sample size 'n' = 200

Given Thirty of the messages were not business related

 let 'x' = 30

<em>Probability of the messages were not business related or proportion</em>

<em></em>p = \frac{x}{n} = \frac{30}{200} = 0.15<em></em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>The 90% confidence interval for the population proportion is</em>

(p - Z_{0.10} \sqrt{\frac{p(1-p)}{n} } , p + Z_{0.10} \sqrt{\frac{p(1-p)}{n} } )

Level of significance ∝ = 0.90 or 0.10

The critical value   Z₀.₁₀ = 1.645

<em>The 90% confidence interval for the population proportion is</em>

(  0.15-1.645 \sqrt{\frac{0.15(1-0.15)}{200} } , 0.15 +1.645 \sqrt{\frac{0.15(1-0.15)}{200} } )

on calculation, we get

(0.15 - 0.04128 , (0.15 + 0.04128)

(0.10872, 0.19128)

<u><em> Conclusion:-</em></u>

<em> The 90% confidence interval for the population proportion is</em>

<em>(0.10872, 0.19128)</em>

<em></em>

5 0
3 years ago
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