1. 15
2. 5
3. Flashcards
Pretty sure this is right, good luck!
Answer:
0.1296
Step-by-step explanation:
The desired probability is calculated by using geometric probability distribution having the pdf of
P(X=r)=p*q^r-1 where x=1,2,3,....
The geometric distribution is used because experiment is repeated various number of times until the success is obtained.
Here p is the probability of success which is 0.4 in the given scenario as Zach scores a ringer 40% percent of time
We wish to calculate the probability that Zach throws 555 or more to achieve his first ringer that is
P(R≥5)=1-P(R<5)=1-P(R≤4)
P(R≤4)=P(R=1)+P(R=2)+P(R=3)+P(R=4)
P(R≤4)=0.4*0.6^0+0.4*0.6^1+0.4*0.6^2+0.4*0.6^3
P(R≤4)=0.4+0.4*0.6+0.4*0.36+0.4*0.216
P(R≤4)=0.8704
P(R≥5)=1-P(R≤4)=1-0.8704=0.1296.
So it is 12.96% chance that the Zach throws 555 or more to achieve his first ringer.
D=11.25
You can make a proportion of the bigger triangle to the smaller triangle
8/15=6/d
cross multiply
8d=90
d=11.25<span />
Answer:
Ratio = 
Step-by-step explanation:
Volume of Sphere is given by the formula:
Where
V is the volume
and
r is the radius
Original Volume, given r = 3, would be:
Increased snowball volume:
Radius increased 0.25 per second, he spent 4 seconds, so radius increase:
0.25 * 4 = 1 cm
New radius = 3 + 1 = 4 cm
New Volume would be:
Ratio of New Volume to Original would be:
This is the ratio for current volume to original volume.
Complete question :
Suppose there are n independent trials of an experiment with k > 3 mutually exclusive outcomes, where Pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this situation?
Answer: Ei = nPi
Step-by-step explanation:
Since Pi represents the probability of observing the ith outcome
The number of independent trials n = k>3 :
Expected outcome of each count will be the product of probability of the ith outcome and the number of the corresponding trial.
Hence, Expected count (Ei) = probability of ith count * n
Ei = nPi
