An equation of a line parallel to y=x-6, must have the same slope.
In this equation:
y=mx+b (slope-intercept form)
m is the slope:
The slope of the equation y=x-6 is m=1 (the number beside "x").
Now we have a point (-1,5) and the slope m=1.
Point-slope form of a line:
y-y₀=m(x-x₀)
so:
y-5=1(x+1)
answer: the equation of the line in point-slope form is :
y-5=1(x+1)
And the eqution of this line in slope-intercept form is:
y=x+6
y-5=(x+1)
y=x+1+5
y=x+6
The first one!! it should be correct
Midsegments are line segments that connect the midpoints of a triangle. If we have the condition that QR = NP, we have the equation
3x + 2 = 2x + 16
Solving for x
3x - 2x = 16 - 2
x = 14
Therefore, x is 14. <span />
Answer:
c trust me
and well i just did that 20 mins ago
Answer:
x+y=-5.75
Step-by-step explanation:
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Well, you would simply need to use the distributive property!
-(2)x-(2)2+(2)y-(2)9=1
-2x-4+2y-18=1
Then you need to add/subtract so the similar numbers are together.
-2x+2y-22=1
-2x+2y=23
x+2y=-11.5
x+y=-5.75
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