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3 years ago

A six-sided number cube is rolled. Find the probability of rolling a 3 or a number greater than 4. A. 1/18 B. 1/6 C. 1/2 D. 2/3

Mathematics

1 answer:

ale4655 [162]3 years ago

3 0

The answer is C.1/2 because there is only possible numbers are 3,5,6.

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Tell whether the ratios form a proportion.<br><br> 13,721

kenny6666 [7]

Answer is N/A. There is not a ratio to answer the question.

7 0

3 years ago

Solve the absolute value equation below 3|6-4x|-4=

egoroff_w [7]

Answer:

Impossible, not enough to answer the question

Step-by-step explanation:

As you can see because there is no number or variable past the equal sign it is simply an expression, please correct me if I am wrong but even if the other side was 0, I doubt a teacher would give this problem with decimals, but it may just be me.

7 0

3 years ago

From 10:00 am to noon, the rise in temperature is 4 degrees C, and from 3:00 pm to 5:00 pm, the fall in temperature is 6 degrees

lyudmila [28]

Answer:

(a) 2 degree celsius per hour

(b) 3 degree celsius per hour.

Step-by-step explanation:

From the question,

(a) Avearge rate of rise in temperature per hour(T') = Rise in temperature(T)/Time required for the rise(t).

T' = T/t.................... Euqation 1

Rise in temperature (T) = 4 degree celsius, t = 10.00 am to noon = 2 hours.

Substitute into equation 1

T' = 4/2

T' = 2 degree celsius per hour.

(b) Also,

Average rate of fall in temperature per hour (T') = Fall in temperature (T)/Time(t)

T' = T/t

Given: T = 6 degree celsius, t = 3:00 pm to 5:00 pm = 2 hours

T' = 6/2

T' = 3 degree celsius per hour

3 0

3 years ago

Determine the sample size needed to construct a 90% confidence interval to estimate the population proportion when p = 0.65 and

WINSTONCH [101]

Answer:

n=170

Step-by-step explanation:

1) Notation and definitions

$n$ random sample taken (variable of interest)

$\hat p=0.65$ estimated proportion.

$p$ true population

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: