Answer:
Step-by-step explanation:
they want you to remember your algebra... :P
mulitply both sides by 5
5*
= -7 * 5 this is fair.. b/c you have done the same thing to both sides of the equal sign... the equal sign remains true
now cancel the 5 s on the left
x = -35 and voila you got it
Let a be the constant the quadratic term
y = ax²
32 = a(2)²
a = 8
Using the same method for each pair of x and y, we can confirm that the value of a is 8.
The answer is A.
![\bf \sqrt{(x^2-1)^2} = x^2-1\implies \sqrt[2]{(x^2-1)^2} = x^2-1\implies (x^2-1) = x^2-1 \\\\\\ 0 = 0\qquad \impliedby \begin{array}{llll} \textit{dependent consistent system}\\ \textit{infinitely many solutions} \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Csqrt%7B%28x%5E2-1%29%5E2%7D%20%3D%20x%5E2-1%5Cimplies%20%5Csqrt%5B2%5D%7B%28x%5E2-1%29%5E2%7D%20%3D%20x%5E2-1%5Cimplies%20%28x%5E2-1%29%20%3D%20x%5E2-1%20%5C%5C%5C%5C%5C%5C%200%20%3D%200%5Cqquad%20%5Cimpliedby%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Ctextit%7Bdependent%20consistent%20system%7D%5C%5C%20%5Ctextit%7Binfinitely%20many%20solutions%7D%20%5Cend%7Barray%7D)
whenever we end up with an expression on the left-hand-side that is equal to the equation on the right-hand-side, is a way of saying, the system of equations, contains two lines that are exactly the same thing, but one is in disguise, something like say
9x + 15 = (3x + 5)3
now, if we distribute the 3 on the right-hand-side, we'd end up with the same equaton on the left-hand-side, so both are the same.
graphing wise, a solution is where both graphs intersect, when two equations are equal they'll intersect, well, at every single point, since their graph is really just one graph pancaked on top of the other, since they touch each other at every point, infinitely many solutions.
Answer:
8w=48
This answer can be simplified by dividing both sides which contain the variable, which in this case is 8. Dividing 48 by 8 gets 6. This means that w equals 6.
Answer: None
Step-by-step explanation: You need more info to answer that question so I would just put that you don’t know much about the question.