Question

G(x) = –16x + x2 in vertex form.

Answer 1

Answer:

$g(x)=(x-8)^2-64$

Step-by-step explanation:

The given function is;

$g(x)=-16x+x^2$

This is the same as;

$g(x)=x^2-16x$

Add and subtract the square of half the coefficient of x.

$g(x)=x^2-16x+(-8)^2-(-8)^2$

Observe that the first three terms is a perfect square trinomial.

$g(x)=(x-8)^2-64$

The vertex form is $g(x)=(x-8)^2-64$

The vertex (8,-64)