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Wewaii [24]
3 years ago
12

Before it started to rain, Bobby cut 1 8 of the grass in his yard and Danny cut 1 5 of the grass in the yard. Both boys were dis

appointed because they were not able to cut the entire yard.
Which statement is TRUE?

A)Together the boys didn't even cut half the yard. B) The boys were able to cut more than half the yard. C) The boys cut almost three-fourths of the yard. D) Together the boys cut almost the entire yard.
Mathematics
jasmie
2 years ago
do you knw your math why are you talking little lady
2 answers:
Serggg [28]3 years ago
5 0

It’s B. The boys were able to cut more than half the yard.

blsea [12.9K]3 years ago
4 0

Answer:

A) Together the boys didn't even cut half the yard.

Step-by-step explanation:

The amount cut was ...

1/8 + 1/5 = 5/40 +8/40 = 13/40

This amount is less than half = 20/40, so choice A is appropriate.

_____

You can reason about these fractions several ways:

1. half is 2 1/2 fifths. 1/8 is less than 1/5, so 1/5+1/8 < (2 1/2)/5.

2. half is 4/8. 1/5 is more than 1/8 but is less than 2/8. 1/8 + 1/5 < 3/8 < 1/2

3. 1/5 < 1/4; 1/8 < 1/4; 1/2 = 2/4, so two amounts less than 1/4 cannot be more than 1/2.

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What k-1/3=5/6 equal ?
JulijaS [17]
The value of "K"

k -\frac{1}{3} = \frac{5}{6}

MMC (3,6)
3,6 | 3
1,2 | 2
1,1 |__ 3*2 = 6

Solving:
k -\frac{1}{3} = \frac{5}{6}
\frac{6k}{6} - \frac{2}{6} = \frac{5}{6}
cancel denominators (6)
6k - 2 = 5
6k = 5+2
6k = 7
\boxed{k =  \frac{7}{6} }


7 0
3 years ago
How do you solve a proportion? (Like not how To but What do i do Because the question Is how do you solve a proportion.)
maksim [4K]

Answer:

By cross-multiplying?

3 0
3 years ago
One day at St. Philip's High School, 1/2 of the pupils walked to school, 1/5 of the pupils came to school by bus, and the remai
Doss [256]
Let P be the number of kids,
we know P>57
take 1-(1/2)-(1/5)=3/10
therefore 57 is 3/10P
3/7P=57
P=57*7/3=133 is the answer
it would be incorrect if we didnt get a positive integer.
7 0
4 years ago
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
Mr. Addis drove 136 miles on 8 gallons if gas. What is the unit rate?
barxatty [35]

Answer:

17 i think

Step-by-step explanation:

6 0
3 years ago
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