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Dennis_Churaev [7]
3 years ago
7

Equivalent express15n+5n

Mathematics
2 answers:
makkiz [27]3 years ago
6 0
♥ Let's solve:

15n+5n can be known as 15+5.

15+5=20 now add n.

Final answer: 20n
Anna35 [415]3 years ago
4 0
15n + 5n 

Combine like terms. 

15 + 5 = 20

20 * n = 20n

Answer: 20n
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Slope = 2; 3-intercept=-1
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Answer: Slope = 2; 3-intercept=-1

Step-by-step explanation:

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"A cylindrical container has a radius of 25 inches and a height of 31 inches. What is the volume of
photoshop1234 [79]

Use the formula:

Radio= r, Height= h

V= 3.14xrx2h

r =25, h=31

V= 3.14 x 25 x 2 (31) =. 4867

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Step-by-step explanation:

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Hannah wants to buy a new shirt the original price is 32.75 but it is on sale for 40% off . what is sale price of the shirt
kati45 [8]
1) 32.75 times .40= 13.10
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3 years ago
Jennifer is saving money to buy a bike. The bike costs $246. She has $138 saved, and each week she adds $18 to her savings.
Brrunno [24]

Answer: 8 weeks

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6 0
3 years ago
Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
1 year ago
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