Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration:
, where 
is the final velocity in a direction after the acceleration is applied, 
is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied. - <em>Then for the x direction</em> it is known that the initial velocity is
5320 m/s, the acceleration (the applied by the engine) in x direction is 
1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: 
- In the same fashion, <em>for the y direction</em>, the initial velocity is
0 m/s, the acceleration in y direction is 
7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: 
Answer:
4 times
Step-by-step explanation:
You divide 12 by 3
It is a trick question 13+13 DOES equal 26
It would be obtuse.
Hope this helps :)
Y = (37.50/5)x
y = 7.50x
Graph: Since the graph will start at the origin (0,0) and has a constant rate of $7.50 per hour, the graph will be linear and in proportion. Some cooridinate are as follows:
x: 0 1 2 3 4 5 ....(add 1...)
y: 7.5 15 22.5 30 37.50 45....(add 7.50...)
