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3 years ago

Multiply or divide as Indicated. x^-8 divided by x^-7

Mathematics

1 answer:

Llana [10]3 years ago

3 0

Answer:

x^1

Step-by-step explanation:

if you divide exponents with the same coefficients, you subtract the two exponents

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Simplify. (–28xy) ÷ (–4) −7xy 17ab −17ab 7xy

astra-53 [7]

If any doubt leave a comment

6 0

3 years ago

Elena bikes 20 minutes each day for exercise. Write an equation to describe the relationship between her distance in miles, D, a

kompoz [17]

Answer:

The equation to describe the relationship between Elena distance:

a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

Solution:

Given, Elena bikes 20 minutes each day for exercise.

We have to write an equation to describe the relationship between her distance in miles, D, and her biking speed, in miles per hour,

We know that, distance travelled = speed $\times$ time

a. At a constant speed of 13 miles per hour for the entire 20 minutes

Her speed is 13 miles per hour.

Then, distance D miles = 13 miles per hour $\times$ 20 minutes

$\mathrm{D}=13 \text { miles per hour } \times \frac{20}{60} \text { hours } \rightarrow \mathrm{d}=13 \times \frac{1}{3} \rightarrow \mathrm{d}=4.34 \text { miles approximately. }$

b. At a constant speed of 15 minutes per hour for the first 5 minutes, then at 12 miles per hour for the last 15 minutes

Now, total distance travelled = distance travelled with 15 mph + distance travelled with 12 mph

$\begin{array}{l}{\mathrm{D}=15 \mathrm{mph} \times 5 \text { minutes }+12 \mathrm{mph} \times 15 \text { minutes }} \\\\ {\mathrm{D}=15 \mathrm{mph} \times \frac{5}{60} \text { hours }+12 \mathrm{mph} \times \frac{15}{60} \text { minutes }} \\\\ {\mathrm{D}=15 \times \frac{1}{12}+12 \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{5}{4}+3 \rightarrow \mathrm{D}=3+1.25 \rightarrow \mathrm{D}=4.25 \mathrm{miles}}\end{array}$

c. At a constant speed of M miles per hour for the first 5 minutes, then at N miles per hour for the last 15 minutes

Now, total distance travelled = distance travelled with M mph + distance travelled with N mph

$D = M mph \times 5 minutes + N mph \times 15 minutes$

$\mathrm{D}=\mathrm{M} \mathrm{mph} \times \frac{5}{60} \text { hours }+\mathrm{N} \mathrm{mph} \times \frac{15}{60} \text { minutes }$

$\mathrm{D}=\mathrm{M} \times \frac{1}{12}+\mathrm{N} \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{M}{12}+\frac{N}{4} \rightarrow \mathrm{D}=\frac{M}{12}+\frac{3 N}{12} \rightarrow 12 \mathrm{D}=\mathrm{M}+3 \mathrm{N} \text { miles }$

Hence, a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

8 0

4 years ago

A certain restaurant sells coffee for 2.00 and donuts for 1.50. If the restaurant sold 80 items and earned 141.50 how many donut

Korvikt [17]

Answer:

$280

Step-by-step explanation:

if you do 2.00+1.50 you get 3.50. Then you do 3.50 ×80 you get 280 dollars

6 0

4 years ago

What is the answer to this question??

MAXImum [283]

Answer:

28.246

Step-by-step explanation:

hihi. So you can use the Pythagorean theorem to find any missing sides to a triangle. The equation goes like this: a^2 + b^2 = c^2, where a a and b are the lengths of the 2 bases of the triangle and c is the length of the hypothenuse/longest side to the triangle. Since you know the length of the hypothenuse and of one of the bases you can solve for the last base using the equation which gets you ~8.246. Now, adding that to the other side lengths gets you 28.246 as an approximate perimeter to 3 sig figs

4 0

3 years ago

If MP = 6x – 5, QR = 3x + 1, and RN = 6, what is QN?

NeTakaya

Answer:

19 units.

Step-by-step explanation:

Consider the below figure attached with this question.

From the below figure it is given that MN=PQ.

It is given that MP = 6x – 5, QR = 3x + 1, and RN = 6.

Since non parallel sides are equal, therefore it is an isosceles trapezoid.

The diagonals of an isosceles trapezoid are equal.