Answer:
17 in
Step-by-step explanation:
H²= 8²+15²
H²= 64+225
H²=289
H= √289
H= 17
17 in. (option C)
Pythagorean Theorem: a² + b² = c²
Set the hypotenuse as x.
8² + 15² = x²
Simplify.
x² = 289
Remove the square from both sides.
x = √289 = 17
Thus, the answer is C, 17.
x, StartFraction x Over 2 EndFraction, StartFraction x Over 4 EndFraction, StartFraction x Over 8 EndFraction, ellipsis
1/8
![\frac{V_1}{V_2}=k^3 \\ \\ \frac{320 \ cm^3}{1080 \ cm^3}=k^3 \\ \frac{8}{27}=k^3 \\ k=\sqrt[3]{\frac{8}{27}} \\ \boxed{k=\frac{2}{3}} \Leftarrow \hbox{answer B}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BV_2%7D%3Dk%5E3%20%5C%5C%20%5C%5C%0A%5Cfrac%7B320%20%5C%20cm%5E3%7D%7B1080%20%5C%20cm%5E3%7D%3Dk%5E3%20%5C%5C%0A%5Cfrac%7B8%7D%7B27%7D%3Dk%5E3%20%5C%5C%0Ak%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B8%7D%7B27%7D%7D%20%5C%5C%0A%5Cboxed%7Bk%3D%5Cfrac%7B2%7D%7B3%7D%7D%20%5CLeftarrow%20%5Chbox%7Banswer%20B%7D)