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Vesna [10]
3 years ago
7

Please ASAP answer this question:)

Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0

Answer:

17 in

Step-by-step explanation:

H²= 8²+15²

H²= 64+225

H²=289

H= √289

H= 17

tankabanditka [31]3 years ago
5 0

Answer:

17 in. (option C)

Step-by-step explanation:

Pythagorean Theorem: a² + b² = c²

Set the hypotenuse as x.

8² + 15² = x²

Simplify.

x² = 289

Remove the square from both sides.

x = √289 = 17

Thus, the answer is C, 17.

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9 + (-8) using a number line
Lelu [443]

Answer:

9 + (-8) = 1

Step-by-step explanation:

4 0
2 years ago
Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2
igor_vitrenko [27]

Answer:  The required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Step-by-step explanation:  We are given to find the solution of the following initial value problem :

y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.

Let y=e^{mx} be an auxiliary solution of the given differential equation.

Then, we have

y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.

Substituting these values in the given differential equation, we have

m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.

So, the general solution of the given equation is

y(x)=Ae^x+Be^{-x}, where A and B are constants.

This gives, after differentiating with respect to x that

y^\prime(x)=Ae^x-Be^{-x}.

The given conditions implies that

y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Adding equations (i) and (ii), we get

2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.

From equation (i), we get

\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.

Substituting the values of A and B in the general solution, we get

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Thus, the required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

4 0
3 years ago
What is the least common multiple of 100,14,20
Tema [17]

Answer:

I believe the answer is 2 :)

Step-by-step explanation:

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Please help WILL GIVE BRAINLIEST! find the missing triangle measurements
dimaraw [331]

ABC=50

DCE=65

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I hope that helps I would appreciate brainliest if possible :)

5 0
2 years ago
Kirsty counts the number of peas in a sample of pea pods.
zaharov [31]

Answer:

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