There are 36 outcomes when rolling a pair of dice.
The ones adding up to 8 are: (2,6),(3,5),(4,4),(5,3),(6,2).
So the probability of rolling a sum of 8 is 5/36.
With three (independent) random throws, the probability of having a sum of 8 at least once equals 1-probability of no 8 at all.
P(not 8)=1-5/36=31/36
For this to happen three times, we use the multiplication rule
P(not 8 three times)=(31/36)^3=29791/46656=
Therefore
P(sum of 8 at least once)=1-29791/46656=16865/46656
[=0.3615 approx.]
Brett deposited $150.00 in an account that paid 3% simple interest. the interest brett earn in 5 years :
simple interest = Pricipal x interest rate x number of years
= 150 x 0.03 x 5
= $ 22.50
hope this help
When solving for you it would equal 6 so U=6 hope that helps
Answer:
500
Step-by-step explanation:
50=t/10
Move the equation over the equal sign which means you change the operation from division to multiplication
50*10 = 500
Answer:
24
Step-by-step explanation:
Jayla has a couple of options for cutting her original piece of paper.
- she can cut the 3 inch length from the long dimension of the paper, giving her 5 strips from the length and 4 strips from the width for a total of 20 3×2 pieces
- she can cut the 3 inch length from the short dimension of the paper, giving her 3 strips from the 9-inch width, and 8 strips from the 16-inch length, for a total of 3×8 = 24 pieces.
The greatest number of 3×2 pieces Jayla can cut is 24.
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The attachments show the different cuts as described above.