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VashaNatasha [74]
3 years ago
11

Ellen wants to purchase a book that is regularly priced at $18. The book is discounted 15%. She also needs to pay a 6% sales tax

on the discounted price.
What is the total amount Ellen will pay for the book?

Enter your answer in the box.
Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0

Answer:

so the other guy can get Brainliest

Step-by-step explanation:

Aloiza [94]3 years ago
3 0
15% of 18 .
so. 18×15)÷100= 2.7
18-2.7= 15.3
now 6% of 15.3.
so 6×15.3)÷100=0.918 or 0.92
15.3+0.92=16 .22
answer is 16.22$
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58 - 5X = 30X - 75 need help please
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Answer:

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Step-by-step explanation:

58-5x=30x-75

Let's add 5x to both sides of the equation...

58=35x-75

Then, let's add 75 to both sides of the equation...

133=35x

Divide by the coefficient of x, (35)...

x=3.8

7 0
3 years ago
If (x − 2) ∶ 5 = 7 ∶ 9, then find the value of x.
WARRIOR [948]

Answer:

x=53/9

Step-by-step explanation:

(x-2):5=7:9

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9x=35+18

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3 years ago
The number of responses to a survey are shown in the Pareto chart. The survey asked 1052 adults how they would grade the quality
Goryan [66]

Answer: (a) P(no A) = 0.935

              (b) P(A and B and C) = 0.0005

              (c) P(D or F) = 0.379

              (d) P(A or B) = 0.31

Step-by-step explanation: <u>Pareto</u> <u>Chart</u> demonstrates a relationship between two quantities, in a way that a relative change in one results in a change in the other.

The Pareto chart below shows the number of people and which category they qualified each public school.

(a) The probability of a person not giving an A is the difference between total probability (1) and probability of giving an A:

P(no A) = 1-\frac{68}{1052}

P(no A) = 1 - 0.065

P(no A) = 0.935

b) Probability of a grade better than D, is the product of the probabilities of an A, an B and an C:

P(A and B and C) = (\frac{68}{1052})(\frac{258}{1052})(\frac{327}{1052})

P(A and B and C) = \frac{5736888}{1164252608}

P(A and B and C) = 0.0005

c) Probability of an D or an F is the sum of probabilities of an D and of an F:

P(D or F) = \frac{269}{1052} +\frac{130}{1052}

P(D or F) = \frac{399}{1052}

P(D or F) = 0.379

d) Probability of an A or B is also the sum of probabilities of an A and of an B:

P(A or B) = \frac{68}{1052} +\frac{258}{1052}

P(A or B) = \frac{326}{1052}

P(A or B) = 0.31

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