To solve for AC in the given inscribed angle we proceed as follows:
An inscribed angle is an angle with its vertex "on" the circle formed by two intersecting chords as in our drawing. Thus here we shall use the formula:
Inscribed Angle=1/2 intercepted Arc
thus
m∠ABC=1/2mAC
thus plugging in our values we shall have:
4x-3.5=1/2(4x+17)
4x-3.5=2x+8.5
solving simplifying and solving for x we obtain
4x-2x=8.5+3.5
2x=12
hence
x=12/2
x=6°
The least common denominator is 5y, and can be obtained by multiplying
-1/y by 5/5 to get -5/5y.
If we add the numbers using the least common denominator, we get:
-5/5y + 2/5y = -3/5y
-4x/7 > 10
Multiply both sides by 7:
-4x > 70
Divide both sides by -4"
x > 70 / -4
Simplify the fraction:
70/-4 = 35 / -2
Because the fraction is negative you need to reverse the inequality sign:
x < -35/2
The answer is the first one: {x|x < -35/2}
Answer:
- Least Value = 2
- Median = 6
- Greatest Value = 10
- Third Quartile = 8
- Range = 8 (10 - 2 = 8)
- First Quartile = 5
Step-by-step explanation:
Given:
The two functions are:
![g(b)=5b-9](https://tex.z-dn.net/?f=g%28b%29%3D5b-9)
![h(b)=(b-1)^2](https://tex.z-dn.net/?f=h%28b%29%3D%28b-1%29%5E2)
To find:
The value of
.
Solution:
We have,
![g(b)=5b-9](https://tex.z-dn.net/?f=g%28b%29%3D5b-9)
![h(b)=(b-1)^2](https://tex.z-dn.net/?f=h%28b%29%3D%28b-1%29%5E2)
We know that,
![(h\circ g)(b)=h(g(b))](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3Dh%28g%28b%29%29)
![(h\circ g)(b)=h(5b-9)](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3Dh%285b-9%29)
![(h\circ g)(b)=[(5b-9)-1]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B%285b-9%29-1%5D%5E2)
![(h\circ g)(b)=[5b-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B5b-10%5D%5E2)
Putting
, we get
![(h\circ g)(-6)=[5(-6)-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B5%28-6%29-10%5D%5E2)
![(h\circ g)(-6)=[-39-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-39-10%5D%5E2)
![(h\circ g)(-6)=[-49]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-49%5D%5E2)
![(h\circ g)(-6)=2401](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D2401)
Therefore, the value of
is 2401.