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Anuta_ua [19.1K]
3 years ago
14

Round 8.1845062 to the nearest hundred thousandths

Mathematics
1 answer:
balandron [24]3 years ago
6 0
8.1845062 

8.1845   << your answer.

the number 5 was in the hundred thousandths so to round it look at the next number and if it's less than 5, it stays the same but if it's more than 5 you round it up to the next number.

hope this helps, God bless!
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Factor completely x^3 + 1/8
maksim [4K]

Answer:

((2 x + 1) (4 x^2 - 2 x + 1))/8

Step-by-step explanation:

Factor the following:

x^3 + 1/8

Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:

(8 x^3)/8 + 1/8

(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:

(8 x^3 + 1)/8

8 x^3 + 1 = (2 x)^3 + 1^3:

((2 x)^3 + 1^3)/8

Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):

((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8

1^2 = 1:

((2 x + 1) ((2 x)^2 - 2 x + 1))/8

Multiply each exponent in 2 x by 2:

((2 x + 1) (2^2 x^2 - 2 x + 1))/8

2^2 = 4:

Answer:  ((2 x + 1) (4 x^2 - 2 x + 1))/8

5 0
3 years ago
Read 2 more answers
3x + ky = 8
sattari [20]

Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>

<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

{ \bf{y =  \frac{1}{2} }} \\ { \sf{ky =  - 1}} \\ { \sf{k =  - 2}}

4 0
3 years ago
Whats the answer for number 3
Karolina [17]

cant see the full question ;/

5 0
3 years ago
A triangle has an area of 24 square units. Its height is 6 units.
devlian [24]
Area of triangle=1/2 times base times  height
given that area=24 and height=6
24=1/2 times base times 6
24=1/2 times 6 times base
24=3 times base
divide both sides by 3
8=base
the base is 8 units long
4 0
3 years ago
Read 2 more answers
A bank manager wants to encourage new customers to open accounts with principals of at least ​$2 comma 500. He decides to make a
prisoha [69]

Answer:

To earn $10 in 1st month, the principal must be $4,000.

No, the poster cannot claim that "Open an account of ​$2 comma 500 and earn at least ​$10 interest in 1​ month!".

Step-by-step explanation:

We have been given that a bank manager wants to encourage new customers to open accounts with principals of at least ​$2,500. He decides to make a poster advertising a simple interest rate of 3​%. We are asked to find the principal to advertise that one can earn ​$10 the first​ month.

We will use simple interest formula to solve our given problem.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

r=3\%=\frac{3}{100}=0.03

1 month will be equal to \frac{1}{12}.

\$10=P\cdot0.03\cdot \frac{1}{12}

\$10=0.0025P

\frac{\$10}{0.0025}=\frac{0.0025P}{0.0025}

P=\$4000

Therefore, to earn $10 in 1st month, the principal must be $4,000.

Now, we will check if an account of ​$2,500 can earn at least ​$10 interest in 1​ month.

I=\$2500\cdot 0.03\cdot \frac{1}{12}

I=\$6.25

Since the account earns an amount of $6.25 in one month, therefore, the poster is not true.

4 0
3 years ago
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