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never [62]
3 years ago
6

Please answer all questions step by step PLEASE HELPP!!!! I'LL MARK YOU AS BRAINLIEST

Mathematics
2 answers:
garri49 [273]3 years ago
4 0

Answer:

3. -2(3m + 9) = -6m - 11

4. -6(z-1) = -6z + 6

5. -(m +1) = -m - 1

6.  -(x+4) = x = 4

7.  b(a- 6) = ab - 6b

8. 7a(3b -2c + 4) = 21ab - 14ac +28a

9. 1/2(8x + 2) = 4x + 1

10. 2/3(1/4x -6) = 1/6x - 4

Step-by-step explanation:

Gre4nikov [31]3 years ago
3 0

I think your teacher's just asking for the multiplied out version, so there's no work to do

3. -2(3m + 9) = -6m - 11

4. -6(z-1) = -6z + 6

5. -(m +1) = -m - 1

6.  -(x+4) = x = 4

7.  b(a- 6) = ab - 6b

8. 7a(3b -2c + 4) = 21ab - 14ac +28a

9. 1/2(8x + 2) = 4x + 1

10. 2/3(1/4x -6) = 1/6x - 4

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The book fair had a sale where 4 books were $25.64. If you wanted to buy 6 books, how much money would you need?
Serjik [45]
$38.46

work-
25.64/4 =6.41
6.41*6=38.46
so you will need a total of $38.46 to buy 6 books.
hope this helped!
7 0
4 years ago
Graph f(x)=−0.5x+3. Use the line tool and select two points to graph the line.
NikAS [45]

Answer: These are some points of the grahp:

(-2,4)

(0, 3)

(2, 2)


Explanation:


1) f(x) =  -0.5x + 3, is the equation of the form y = mx + b


2) y = mx + b is slope-intercept  equation of a line where the slope is m and the y-intercept is b, so, f(x) = - 0.5x + b has slope m = -0.5 and y-intercept b = 3.


3) To graph f(x) = -0.5x + 3, follow these steps:

  • draw two perpedicular axis: vertical axis, labeled y, and horizontal axis, labeled x.
  • draw marks on each axis, each mark equivalent to one unit.
  • the intersection point of the vertical and horizontal axis is the origin, i.e. point (0,0).
  • you can make a table with two or more points:

        x       f(x) = - 0.5x + 3

        -2         4

        0          3

        2          2

        4           1

        6          0


4) You can see the graph in the figure attached, and select any of the points on the line either by using the table or by using the equation f(x) = -0.5x + 3.

8 0
4 years ago
Read 2 more answers
3. A charity had a stall at a fair selling crafts and cakes to raise money.
AveGali [126]

15% of £70= £10.5

Expenditure =£24+£10.5=£34.5

Net amount raised =gross amount - Expenditure

=£70-£34.5=£35.5

3 0
3 years ago
PLEASE IM IN CLASSS RIGHT NOWWW
matrenka [14]
Im guessing 3 i really dont know.. i dont understand what it means by 4 channels.
6 0
3 years ago
The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge
Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

5x+4y+5z=-1

x+y+2z=1

2x+y-z=-3

Firs we find determinant of system of equations

Let a matrix A=\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right] and B=\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]

\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}

\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply R_1\rightarrow R_1-4R_2 and R_3\rightarrow R_3-2R_2

\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]:\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]

ApplyR_2\rightarrow R_2-R_1

\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]:\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]

Apply R_3\rightarrow R_3+R_2

\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]:\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]

Apply R_3\rightarrow- \frac{1}{2} and R_2\rightarrow R_2-R_3

\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]:\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]

Apply R_1\rightarrow R_1-R_3

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]:\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0
4 years ago
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