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3 years ago

Please answer all questions step by step PLEASE HELPP!!!! I'LL MARK YOU AS BRAINLIEST

Mathematics

2 answers:

garri49 [273]3 years ago

4 0

Answer:

3. -2(3m + 9) = -6m - 11

4. -6(z-1) = -6z + 6

5. -(m +1) = -m - 1

6. -(x+4) = x = 4

7. b(a- 6) = ab - 6b

8. 7a(3b -2c + 4) = 21ab - 14ac +28a

9. 1/2(8x + 2) = 4x + 1

10. 2/3(1/4x -6) = 1/6x - 4

Step-by-step explanation:

Gre4nikov [31]3 years ago

3 0

I think your teacher's just asking for the multiplied out version, so there's no work to do

3. -2(3m + 9) = -6m - 11

4. -6(z-1) = -6z + 6

5. -(m +1) = -m - 1

6. -(x+4) = x = 4

7. b(a- 6) = ab - 6b

8. 7a(3b -2c + 4) = 21ab - 14ac +28a

9. 1/2(8x + 2) = 4x + 1

10. 2/3(1/4x -6) = 1/6x - 4

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6(y+x)=6y+6x
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3 years ago

Suppose weight of a baby less than 2 months is normally distributed with mean 11.5 lbs and standard deviation 2.7 lbs, what prop

Lera25 [3.4K]

Step-by-step explanation:

First calculate the z-score.

z = (x − μ) / σ

z = (11.07 − 11.5) / 2.7

z ≈ -0.16

From a z-score table:

P(z<-0.16) = 0.4364

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3 years ago

How do you determine the area under a curve in calculus using integrals or the limit definition of integrals?

RSB [31]

Answer:

Please check the explanation.

Step-by-step explanation:

Let us consider

$y = f(x)$

To find the area under the curve $y = f(x)$ between $x = a$ and $x = b$ , all we need is to integrate $y = f(x)$ between the limits of $a$ and $b$ .

For example, the area between the curve y = x² - 4 and the x-axis on an interval [2, -2] can be calculated as:

$A=\int _a^b|f\left(x\right)|dx$

= $\int _{-2}^2\left|x^2-4\right|dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=\int _{-2}^2x^2dx-\int _{-2}^24dx$

solving

$\int _{-2}^2x^2dx$

$\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=\left[\frac{x^{2+1}}{2+1}\right]^2_{-2}$

$=\left[\frac{x^3}{3}\right]^2_{-2}$

computing the boundaries

$=\frac{16}{3}$

Thus,

$\int _{-2}^2x^2dx=\frac{16}{3}$

similarly solving

$\int _{-2}^24dx$

$\mathrm{Integral\:of\:a\:constant}:\quad \int adx=ax$

$=\left[4x\right]^2_{-2}$

computing the boundaries

$=16$

Thus,

$\int _{-2}^24dx=16$

Therefore, the expression becomes

$A=\int _a^b|f\left(x\right)|dx=\int _{-2}^2x^2dx-\int _{-2}^24dx$

$=\frac{16}{3}-16$

$=-\frac{32}{3}$

$=-10.67$ square units

Thus, the area under a curve is -10.67 square units

The area is negative because it is below the x-axis. Please check the attached figure.

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3 years ago

27. Theodore had 24 baseball cards. He sells 1/4 of his cards to Tom, 1/3 of his cards to Larry. How many baseball cards does Th

Oksana_A [137]

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14 baseball cards

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3 years ago