What is the smallest angle of rotational symmetry that maps a regular pentagon onto itself?
2 answers:
Consider the regular pentagon ABCDE, with center (of mass) O.
The central angle O is a complete angle, so its measure is 360°.
It is divided into 5 equal parts, so each of them has a measure of 360°/5=72°.
If we rotate the pentagon, with point O as the center of the rotation, we can map A to any of the other points.
The smallest angle of rotation is the angle which mas A to E, 72°.
Answer: 72°
The central angle O is a complete angle, so its measure is 360°.
It is divided into 5 equal parts, so each of them has a measure of 360°/5=72°.
If we rotate the pentagon, with point O as the center of the rotation, we can map A to any of the other points.
The smallest angle of rotation is the angle which mas A to E, 72°.
Answer: 72°
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Answer:
3.16 units
Step-by-step explanation:
It has been given that the triangles JKL and the triangle RST are congruent.
That implies that, the length of the side JK, KL, and JL is equivalent to the length of the sides RS, ST, and RT respectively.
Now, to find the length of JK we need to find the length of the side RS. The coordinates of the points R and S are and
.
The length of the side RS is equal to the distance between point R and S.
RS
Now that we have the length of the side RS, and the triangles JKL and RST are congruent therefore, the length of the side JK is 3.16 units.
Here we will use exponential form, which is
Initial value, y0 = 500
Double of 500 = 1000
Required equation is