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nataly862011 [7]
3 years ago
6

Find the inverse of the following functions algebraically

Mathematics
1 answer:
Inessa05 [86]3 years ago
4 0
The answer is g^-1= x^2/2 + 1/2
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jenyasd209 [6]
4:6 4’7 4:7 because 4 is into the 15
3 0
3 years ago
Read 2 more answers
Find the Area of ze Trapezoid
Elina [12.6K]
A=a+b/2·h=9+4/2·3.5=22.75

Hoped I helped!
3 0
3 years ago
PLEASE HELP MEEEEEEEEEEEEEEEEE ASAAAAAAAP How many centimeters are in 10 meters? A) 10,000 cm B) 1,000 cm C) 100 cm D) 10 cm
statuscvo [17]

Answer:

1,000 cm......there are 100 cm per meter so 1,000 cm per 10 meters

Step-by-step explanation:

8 0
3 years ago
Explain why sin^-1(sin(3pi/4))does not equal 3pi/4 when y=sin x and y=sin^-1 x are inverses.
Fofino [41]

Because they're not inverses, not exactly. \sin x is not invertible on its entire domain because it's not one-to-one. There are infinitely many values of x such that \sin x=0, for example.

The standard function \sin^{-1}x has a domain of -1\le x\le1 and outputs values between -\dfrac\pi2 and \dfrac\pi2. This means that its inverse, \sin x, is indeed its inverse as long as -\dfrac\pi2\le x\le\dfrac\pi2.

\dfrac{3\pi}4 is larger than \dfrac\pi2 and thus does not fall in the "invertible part" of the domain of \sin x. We have

\sin\dfrac{3\pi}4=\dfrac1{\sqrt2}

which is a value between -1 and 1, so that

\sin^{-1}\left(\sin\dfrac{3\pi}4\right)=\sin^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

If we wanted to recover \dfrac{3\pi}4, we'd have to redefine \sin^{-1}x or define a new inverse function that works on a different branch of the domain of \sin x.

7 0
3 years ago
Which of the following choices shows the equation solved for y
katen-ka-za [31]

Answer:

#1; y = -\frac{7}{2}x+5

Step-by-step explanation:

7x+2y=10

2y = -7x + 10

\frac{2y}{2} = -\frac{7x}{2} + \frac{10}{2}

y = -\frac{7}{2}x + 5

8 0
3 years ago
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