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3 years ago

12

Find the value of x. If necessary, you may learn with the markings on a figure indicate.

1 answer:

love history [14]3 years ago

6 0

Answer:

112

Step-by-step explanation:

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Need help with this math problem

Jet001 [13]

I had to do several calculations to get the answer.

First I calculated how many points each incorrect answer decreased:

6 questions * x = 30 points => x = 30 points / 6 questions = 5 points / question.

Then I converted it in an equation of the kind:

( ) ( ) = 5

And concluded it was 1/6 * 30 = 5

So, the numbers must be placed on either of these two forms:

( 1/6 ) ( 30) = 5, or

( 30 ) ( 1/ 6) = 5.

Of course, both of them are correct answers.

6 0

3 years ago

Find the length of the segment indicated.

laiz [17]

The red square means the triangle is a right triangle so you can solve for x using the Pythagorean theorem.

x = √(16.1^2 - 7.1^2)

x = √(259.21 - 50.41)

x = √208.8

x = 14.4499

Rounded to the nearest tenth x = 14.4

3 0

3 years ago

Read 2 more answers

pablo just moved from cairo to chicago and needs to buy a complete set of winter gear, the store has 2 kinds of parkas and 8 kin

Over [174]

Answer:

64

Step-by-step explanation:

7 0

3 years ago

What are the zeros of the quadratic function f(x) = 2x² + 16x - 9?

jeka57 [31]

The zeros of the quadratic function f(x) = 2x² + 16x - 9 are given as follows:

$x = -4 + \sqrt{\frac{41}{2}}, x = -4 - \sqrt{\frac{41}{2}}$

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

$y = ax^2 + bx + c$

The solutions are:

$x_1 = \frac{-b + \sqrt{\Delta}}{2a}$

$x_2 = \frac{-b - \sqrt{\Delta}}{2a}$

In which:

$\Delta = b^2 - 4ac$

In this problem, the equation is given by:

f(x) = 2x² + 16x - 9.

The coefficients are a = 2, b = 16, c = -9, hence:

$\Delta = 16^2 - 4(2)(-9) = 328$

Then:

$x_1 = \frac{-16 + \sqrt{328}}{2(2)} = -4 + \sqrt{\frac{41}{2}}$

$x_2 = \frac{-16 - \sqrt{328}}{2(2)} = -4 - \sqrt{\frac{41}{2}}$

More can be learned about quadratic functions at brainly.com/question/24737967

#SPJ1

5 0

2 years ago

Quadrilaterals ABCD and PQRS shown below are two similar figures.<br>Find the values of x and y.

nadezda [96]

Answer:

x = 12, y = 16

Step-by-step explanation:

Since the figures are similar then the ratios of corresponding sides are equal, that is

$\frac{AD}{PS}$ = $\frac{DC}{SR}$ , substitute values

$\frac{20}{2x+6}$ = $\frac{18}{27}$ ( cross- multiply )

18(2x + 6) = 540 ( divide both sides by 18 )

2x + 6 = 30 ( subtract 6 from both sides )

2x = 24 ( divide both sides by 2 )

x = 12

-------------------------------------------

and

$\frac{AB}{PQ}$ = $\frac{DC}{SR}$ , substitute values

$\frac{y}{24}$ = $\frac{18}{27}$ ( cross- multiply )

27y = 432 ( divide both sides by 27 )

y = 16

3 0

3 years ago