Question

Wen is factoring the polynomial, which has four terms. 6x3 – 12x2 7x – 14 6x2 (x – 2) 7(x – 2) Which is the completely factored form of his polynomial? (6x2 7) (x –2) (6x2 – 2) (x 7) (6x2 2) (x – 7) (6x2 – 7) (x 2).

Answer 1

The completely factored form of the Wen's polynomial, which has the four terms initial, is,

$(6x^2+7)(x-2)$

What is the factor of polynomial?

The factor of a polynomial is the terms in linear form, which are when multiplied together, give the original polynomial equation as result.

Wen is factoring the polynomial, which has four terms.

$6x^3 - 12x^2+ 7x - 14$ '

Take out the greatest common factor from the equation and make separate groups as,

$6x^2(x - 2)+ 7(x - 2)\\(x-2)(6x^2+7)$

Rearrange the above equation as,

$(6x^2+7)(x-2)$

Thus, the completely factored form of the Wen's polynomial, which has the four terms initial, is,

$(6x^2+7)(x-2)$

Learn more about factor of polynomial here;

brainly.com/question/24380382