Answer:
The output to this given question is "Is it warm: true".
Explanation:
In this question firstly two-variable defines that are isRaining and isCloudy. In those variables assign false value. Then we define another variable that is isSunny. In isSunny variable, we check condition that is if variable isRaining not AND (logical gate) variable isCloudy not equal to isSunny. The AND logical gate is used to check that both condition is true or not. Then we define another variable that is isWarm. In this variable, we check condition if isSunny OR (logical operator) isSummer is true. The OR operator is used to check in both value if one condition will true it will print true. At the last will print the value.
Answer:
All of the above is the correct answer to the given question .
Explanation:
As the Ken olson is the Ken Olson, president of the Digital Equipment Organization . Following are the predictions of Ken olson of the the technology that are wrong.
- Lack of creativity regarding the current applications that the user has would consider for the technology.
- Lack of creativity regarding the user or the client has liking.
- Lack of creativity on what the government would be charging ford. Any of these
So we will choose the Option all these.
A college meal plan allows students to PAY UPFRONT TO EAT A SPECIFIC NUMBER OF MEALS IN THE COLLEGE CAFETERIAS. Many colleges give students some degree of freedom when it comes to the choice of meal plans to sign up for. Students have to pay in advance for any meal they decide for.
Procedure SumEvenOdd(stdin: array [0..100] of integer)
var
i, sum_even, sum_odd: integer;
begin
for i := 0 to 100 do begin
if stdin[i] < 0 then
break;
if stdin[i] mod 2 = 0 then //even number
sum_even := sum_even + stdin[i]
else
sum_odd := sum_odd + stdin[i];
ShowMessage('sum of even is ' + IntToStr(sum_even) + ' ' + 'sum of odd is' + IntToStr(sum_odd) ) ;
end;
end