Answer:
Explanation:
The following code is written in Java. It is a method that calculates the square root of a number as requested. The method first checks with an IF statement if the parameter value is a positive number and then calculates the square root and prints it to the screen. Otherwise, it prints Number must not be negative. A test case has been provided in the main method and the output can be seen in the attached image below.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter a number of type double to calculate square root:");
double num = in.nextDouble();
rootPositive(num);
}
public static void rootPositive(double num) {
if (num > 0) {
System.out.println(Math.sqrt(num));
} else {
System.out.println("Number must not be negative.");
}
}
}
<em>https://todo-anime.com/</em>
Answer:
Option B; 30 SECONDS OR LESS.
Explanation:
Short-term memory, also known as primary or active memory, is the information we are currently aware of or thinking about.
When short-term memories are not rehearsed or actively maintained, they last mere seconds.
Most of the information kept in short-term memory will be stored for less than 30 seconds (approximately 20 to 30 seconds), but it can be just seconds if rehearsal or active maintenance of the information is not done.
Therefore, Anita likely will be able to retain the information in short-term memory, without additional processing, for 30 SECONDS OR LESS.
Cache memory is a high-speed memory that stores the instructions and data that have been frequently accessed. It decreases the time it takes to decode the instructions stored in the instruction pipeline.
A. It decreases the time it takes to decode instructions stored in the instruction pipeline.
<u>Explanation:</u>
Whenever an instruction is invoked or some data is accessed, the CPU looks for it in the cache memory before accessing the main memory.
If the content is found in the cache memory, it accessed from there and then and hence the access time and decode time is reduced as there were no main memory lockups.
