All categories

3 years ago

write a word problem that you can solve by multiplying a mixed number by a whole number. include a solution

2 answers:

7 0

Jessica is doubling a recipe that calls for 1 1/2 cups of milk. How many cups of milk in total does she need?

2 x 1 1/2 = 3

She needs 3 cups of milk in total.

ra1l [238]3 years ago

4 0

1 1/2x5= 7.5 M.A.D.D M=multiplie A.D.D=add 1x2+1=3/2 3/2x5=7.5
7.5 Is the answer

You might be interested in

What’s the slope to these two answers

elena-14-01-66 [18.8K]

Answer:

-5/4 and -7/4

Step-by-step explanation:

3 0

3 years ago

Simplify<br> 7^2x^-3y/49x^-3y^-2

olya-2409 [2.1K]

$\frac{7^2x^{-3}}{49x^{-3} y^{-2}} \\ \\ \frac{49x^{-3}y}{49x^{-3}y^{-2}} \\ \\ \frac{49x^{-3}y}{49x^{-3} \times \frac{1}{y^2} } \\ \\ \frac{49x^{-3}y}{ \frac{49x^{-3}}{y^2} } \\ \\ 49x^{-3} y \times \frac{y^2}{49x^{-3}} \\ \\ \frac{x^{-3}}{x^{-3}} yy^2 \\ \\ 1 \times yy^2 \\ \\ yy^2 \\ \\ y^3 \\ \\$

The answer is: y^3.

4 0

3 years ago

Read 2 more answers

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

Which is true of an adjustable rate mortgage?

stealth61 [152]

Answer:

The rate of interest may vary , totally depends on the market value of that agency or company or the financial agency which is providing the mortgage money at certain rate. So, option (B) the interest rate may change depending on the condition of the economy is true statement regarding adjustable rate mortgage.Step-by-step explanation: hope it helps

5 0

3 years ago

How far would a runner that ran 200 meters in 1/2 minute run in 3 minutes at the same rate?

Igoryamba

Answer:

1,200

Step-by-step explanation:

4 0

2 years ago