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madreJ [45]
3 years ago
15

write a word problem that you can solve by multiplying a mixed number by a whole number. include a solution

Mathematics
2 answers:
Ainat [17]3 years ago
7 0
Jessica is doubling a recipe that calls for 1 1/2 cups of milk. How many cups of milk in total does she need?

2 x 1 1/2 = 3

She needs 3 cups of milk in total.
ra1l [238]3 years ago
4 0
1 1/2x5= 7.5 M.A.D.D M=multiplie A.D.D=add 1x2+1=3/2 3/2x5=7.5
7.5 Is the answer
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What’s the slope to these two answers
elena-14-01-66 [18.8K]

Answer:

-5/4 and -7/4

Step-by-step explanation:

3 0
3 years ago
Simplify<br> 7^2x^-3y/49x^-3y^-2
olya-2409 [2.1K]
\frac{7^2x^{-3}}{49x^{-3} y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3}y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3} \times  \frac{1}{y^2} } \\ \\  \frac{49x^{-3}y}{ \frac{49x^{-3}}{y^2} } \\ \\ 49x^{-3} y \times  \frac{y^2}{49x^{-3}} \\ \\  \frac{x^{-3}}{x^{-3}} yy^2 \\ \\ 1 \times yy^2 \\ \\ yy^2 \\ \\ y^3 \\ \\

The answer is: y^3.
4 0
3 years ago
Read 2 more answers
A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,
algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of \pi/4.

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

d(\theta)=\frac{v_i^2sin(2\theta)}{g}

Where v_i is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is [0, \pi/2]. The critical  points of the function are those who make d'(\theta)=0:

d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}

d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...

The critical value inside the interval is \pi/4.

d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft

The second step is to find the values of the function at the endpoints of the interval:

d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft

The biggest value of f is gived by \pi/4, therefore \pi/4 is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of \pi/4.

4 0
3 years ago
Which is true of an adjustable rate mortgage?
stealth61 [152]

Answer:

The rate of interest may vary , totally depends on the market value of that agency or company or the financial agency which is providing the mortgage money at certain rate. So, option (B) the interest rate may change depending on the condition of the economy is true statement regarding adjustable rate mortgage.Step-by-step explanation: hope it helps

5 0
3 years ago
How far would a runner that ran 200 meters in 1/2 minute run in 3 minutes at the same rate?
Igoryamba

Answer:

1,200

Step-by-step explanation:

4 0
2 years ago
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