Let's say x = full price tickets
Let's say y = student tickets
We can write two equations:
From "585 tickets were sold" we can make the equation:
x + y = 585
And from "Full-price ticket is $2.50 and student ticket is $1.75 and total receipts is $1,217.25"...we can make the equation:
2.50x + 1.75y = 1,217.25
So now we can use substitution to find our answer...since we only have to find how many student tickets...we will solve the first equation for x so we can plug that into the 2nd equation to solve for y.
x + y = 585
x + y - y = 585 - y
x = 585 - y
Now we plug that into our 2nd equation: 2.50 (585 - y) + 1.75y = 1217.25
Distribute your 2.50
1462.5 - 2.50y + 1.75y = 1217.25
Add the y's: 1462.5 - 0.75y = 1217.25
Subtract 1462.5 from both sides:
1462.5 - 0.75y - 1462.5= 1217.25 - 1462.5
-0.75y = -245.25
Divide both sides by -0.75:
y = -245.25/-0.75
y = 327
There were 327 student tickets :)
Answer:
C or the 3rd one
Step-by-step explanation:
Because you know the amount of rings bought but not how much shirts cost
Answer:
13,800,000
Step-by-step explanation:
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The equation y = 3(1.12)^x will double after 6 years.
In order to find this, we need to test all of the numbers in the parenthesis to the 6th power and see which comes closest to 2. We know that after 0 years, each equation will simply have the value of the number outside of the parenthesis, so we need the number inside to be 2 in order to get it to double. The following are each number in the parenthesis raised to the 6th power.
1.50^6 = 11.39
1.17^6 = 2.57
1.06^6 = 1.42
1.12^6 = 1.97
Since the one with 1.12^6 is closest to 2, it is the one that nearly doubles after six years.