Julia spends $2.25 on gas for her lawn mower. She earns $15.00 mowing her neighbors lawn. What is Julia’s profit?

Mathematics

1 answer:

Korolek [52]4 years ago

8 0

Her profit is $ 13.25. It’s simple math all you have to do is subtract. 2.25 - 15.00= 13.25

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Find the value of x when 27 - 2x + 1 = 729+ 2x + 3

vagabundo [1.1K]

Answer:

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3 years ago

Arandom sample of n1 =12 students majoring in accounting in a college of business has a mean grade-point average of 2.70 (where

antiseptic1488 [7]

Answer:

We accept the null hypothesis that the mean gpa's are equal, with the 5 percent level of significance.

Step-by-step explanation:

We have these following hypothesis:

Null

Equal means

$\mu_{1} = \mu_{2}$

Alternative

Different means

$\mu_{1} \neq \mu_{2}$

Our test statistic is:

$\frac{\overline{Y_{1}} - \overline{Y_{2}}}{\sqrt{\frac{s_{1}^{2}}{N_{1}} + \frac{s_{2}^{2}}{N_{2}}}}$

In which $\overline{Y_{1}}, \overline{Y_{2}}$ are the sample means, $N_{1}, N_{2}$ are the sample sizes and $s_{1}, s_{2}$ are the standard deviations of the sample.

In this problem, we have that:

$\overline{Y_{1}} = 2.7, s_{1} = 0.4, N_{1} = 12, \overline{Y_{2}} = 2.9, s_{2} = 0.3, N_{2} = 10$

$T = \frac{2.7 - 2.9}{\sqrt{\frac{0.4}^{2}{12} + \frac{0.3}^{2}{10}}} = -1.3383$

What to do with the null hypothesis?

We will reject the null hypothesis, that is, that the means are equal, with a significante level of $\alpha$ if

$|T| > t_{1-\frac{\alpha}{2},v}$

In which v is the number of degrees of freedom, given by

$v = \frac{(\frac{s_{1}^{2}}{N_{1}} + \frac{s_{2}^{2}}{N_{2}})^{2}}{\frac{\frac{s_{1}^{2}}{N_{1}}}{N_{1}-1} + \frac{\frac{s_{2}^{2}}{N_{2}}}{N_{2} - 1}}$