Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
Answer:
See explaination
Explanation:
import java.util.Scanner;
public class BubbleBubbleStarter {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
double arr[] = new double[10];
System.out.println("Enter 10 GPA values: ");
for (int i = 0; i < 10; i++)
arr[i] = sc.nextDouble();
sc.close();
System.out.println("My list before sorting is: ");
printlist(arr);
bubbleSort(arr);
System.out.println("My list after sorting is: ");
printlist(arr);
}
static void bubbleSort(double[] list) {
boolean changed = true;
do {
changed = false;
for (int j = 0; j < list.length - 1; j++) {
if (list[j] > list[j + 1]) {
double temp = list[j];
list[j] = list[j + 1];
list[j + 1] = temp;
changed = true;
}
}
} while (changed);
}
static void printlist(double list[]) {
for (int j = 0; j < list.length; j++) {
System.out.println(list[j]);
}
}
}
Answer:
False.
Explanation:
The fixed program computer was used earlier which used wired processor and it was very laborious to make changes in processors. In the fixed program, the computer was following the build-in instructions and were processing only those data which were stored in memory.
Stored program computers are used in modern computers that are those computers that have single process structure and which will have instructions on how to perform the function on the computer and how to keep track of the processed data in computation.
Stored program computers keep program instruction in electronic memory.
