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Black_prince [1.1K]
4 years ago
14

What may happen if there is too much harmony in a design?

Computers and Technology
1 answer:
Rudiy274 years ago
5 0

Answer:

B It can seem boring.

Explanation:

The repetition of visual effects results in consistency, rhythm, and movement. However, too much repetition can cause monotony and boredom. And this is not good for you certainly. You are certainly going to lose the audience. And too much harmony in design as well in a similar manner causes boredom, or it can seem boring. And hence, the correct option here is B it can seem boring.

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What is the LER for a rectangular wing with a span of 0.225m and a chord of 0.045m
ch4aika [34]

Calculate LER for a rectangular wing with a span of 0.225m and a chord of 0.045m. The weight of the glider is 0.0500 Newtons. (Note: the wing span is the width of the wing and is measured from wing tip to wing tip, or perpendicular to the fuselage. The wing chord is the length of the wing measured parallel or along the length of the fuselage.)

Answer:

Area of rectangular wing = span × chord = 0.225×0.045= 0.010125m2

LER = Area/weight = 0.010125/0.0500 = 0.2025

4 0
3 years ago
Im Gonna Give Brainly a Second Chance<br><br> Everybody deserves a second chance
Nady [450]

Answer:

ok I know it's not for me but for who?

Explanation:

Just asking. And yes everyone deserves a second chance. Even liars?

please don't take my question wrongly have an above average day!

7 0
3 years ago
Read 2 more answers
Write a program with a main method that asks the user to enter an array of 10 integers. Your main method then calls each of the
Kay [80]

Answer:

The remaining part of the question is given as follows:

printReverse - a void method that reverses the elements of the array and prints out all the elements in one line separated by commas (see sample output below).

getLargest - an int method that returns the largest value in the array.

computeTwice- a method that returns an array of int which contains 2 times of all the numbers in the array (see the sample output below).

Explanation:

// Scanner class is imported to allow the program receive

// user input

import java.util.Scanner;

// Arrays class is imported to allow the program display the array

// in a pretty way

import java.util.Arrays;

//The class definition

public class Solution {

   // main method is defined which signify beginning of program

  // execution

   public static void main(String[ ] args) {

       // an array is initialized with a size of 10

       int[] array =new int[10];

       // Scanner object scan is defined

       Scanner scan =new Scanner(System.in);

       // A loop is initiated to receive 10 user input to fill the array

       for(int i=0; i < 10; i++){

           System.out.print("Please enter number: ");

           array[i]=scan.nextInt();

       }

       

       // A blank line is print

       System.out.println();

       // printReverse method is called with the received array as

      // argument

       printReverse(array);

       // A blank line is print

       System.out.println();

       // The largest number is printed

       System.out.println("The largest number is: " + getLargest(array));

       // computeTwice method is called to display the array after

      // multiplying each element by 2

       computeTwice(array);

       System.out.println( "The values of the computed twice array is: " );

       // Arrays class is used to print the array in form of a string

      // not object

       System.out.println(Arrays.toString(array));

   }

   

   //printReverse method declared with inputArray as parameter.

   // It has no return type

   public static void printReverse(int[] inputArray){

       System.out.print("Here is the arrray in reverse order: ");

       // A loop goes through the array starting from the end

       // and display each element

       for(int i = (inputArray.length - 1); i >= 0; i--){

           if(i == 0){

               // If the last element, do not append comma

               System.out.print(inputArray[i]);

           } else {

               // If not the last element, do append a comma

               System.out.print(inputArray[i] + ", ");

           }

       }

   }

   

   // getLargest method is declared with inputArray as parameter

   //  it compare each element in the array and return the largest

   public static int getLargest(int[] inputArray){

       // The first element is assumed to be the largest before the

      // loop begin

       int max = inputArray[0];

       for(int i = 1; i < inputArray.length; i++){

           if (inputArray[i] > max){

               max = inputArray[i];

           }

       }

       return max;

   }

   

   // computeTwice is declared with inputArray as parameter

   // it loop through the array and multiply each element by 2

   // it then return a modified array

   public static int[] computeTwice(int[] inputArray){

       for(int i = 0; i < inputArray.length; i++){

           inputArray[i] *= 2;

       }

       return inputArray;

   }

}

8 0
3 years ago
The most popular transmission media option for wired home ethernet networks is ________ cable. fiber-optic power-line unshielded
tino4ka555 [31]
<span>This is called an unshielded twisted pair cable, which is also known as a UTP cable. This type of cable has four pairs of wires that are twisted around each other. Because the wires are like this, the electrical interference is reduced.</span>
3 0
4 years ago
c programming Write code that prints: Ready! countNum ... 2 1 Go! Your code should contain a for loop. Print a newline after eac
olga_2 [115]

Answer:see explanation

Explanation:

Hello, from your question I see that you need a program which based on countNum's value prints ready then all the numbers to 1 and finally go!, I'd appreciate if you provided information about the numbers after the example you gave as I do not know if they are to be printed too.

The solution I provide includes the countdown to 1 printing newline after each number and text. Try it out!

#include <stdio.h>

int main(void)

{

   int countNum;

   int i;

   countNum = 22;

   for ( i = countNum; i > 0; i--) {

       if (i == countNum){

           printf("Ready!\n");

       }

       printf("%d\n",i);

   }

   printf("Go!\n");

   return 0;

}

6 0
3 years ago
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