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beks73 [17]
3 years ago
14

3. 8.2(D) Which list shows the numbers in ascending order?

Mathematics
2 answers:
krek1111 [17]3 years ago
7 0

actually none of them since 212 is the biggest number and should be at the end but none of the answers say so

const2013 [10]3 years ago
5 0

Answer:

9/4, 230%, 2.31, 2½, sqrt(8)

Option C

Step-by-step explanation:

sqrt(8), 2½, 2.31, 230%, 9/4

2.8284271247, 2.5, 2.31, 2.3, 2.25

2.25, 2.3, 2.31, 2.5, 2.828..

In ascending order:

9/4, 230%, 2.31, 2½, sqrt(8)

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Which statement shows the associative property of addition?
Savatey [412]

Answer:

D

Step-by-step explanation:

According to the associative property of addition, you can put the parentheses anywhere you like. This is the only one that works.

3 0
3 years ago
Find Each Sum.<br> 1) (-1)+(-46)=<br> 2) (-30)+10=<br> 3) (-34)+50=<br> 4) 38+(-5)=
juin [17]

Answer:

1 is -47.

2 is -20

3 is 16.

4 is 33.

Step-by-step explanation:

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4 0
2 years ago
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There are 5 times as many males as females on the maths course at university. What fraction of the course are female? Give your
koban [17]

Answer: 1/6

Step-by-step explanation: Let the no of females be x

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4 0
3 years ago
[Pre-Calc] Please Help! I don’t know where to start. How do I do this?
sertanlavr [38]

Answer:

See Below.

Step-by-step explanation:

Problem A)

We have:

\displaystyle \csc^2\theta \tan^2\theta -1=\tan^2\theta

When in doubt, convert all reciprocal trig functions and tangent into terms of sine and cosine.

So, let cscθ = 1/sinθ and tanθ = sinθ/cosθ. Hence:

\displaystyle \left(\frac{1}{\sin^2\theta}\right)\left(\frac{\sin^2\theta}{\cos^2\theta}\right)-1=\tan^2\theta

Cancel:

\displaystyle \frac{1}{\cos^2\theta}-1=\tan^2\theta

Let 1/cosθ = secθ:

\sec^2\theta -1=\tan^2\theta

From the Pythagorean Identity, we know that tan²θ + 1 = sec²θ. Hence, sec²θ - 1 = tan²θ:

\tan^2\theta =\tan^2\theta

Problem B)

We have:

\sin^3x=\sin x-\sin x \cos^2 x

Factor out a sine:

\sin x(\sin^2 x)=\sin x-\sin x\cos^2 x

From the Pythagorean Identity, sin²θ + cos²θ = 1. Hence, sin²θ = 1 - cos²θ:

\sin x(1-\cos^2 x)=\sin x-\sin x\cos^2x

Distribute:

\sin x- \sin x \cos^2 x=\sin x-\sin x\cos^2 x

Problem C)

We have:

\displaystyle \frac{\cos 2x+1}{\sin 2x}=\cot x

Recall that cos2θ = cos²θ - sin²θ and that sin2θ = 2sinθcosθ. Hence:

\displaystyle \frac{\cos^2 x-\sin^2 x+1}{2\sin x\cos x}=\cot x

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\displaystyle \frac{2\cos^2 x}{2\sin x\cos x}=\cot x

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3 0
2 years ago
Is 1/3 greater than 5/6
Harman [31]
1/3 or 5/6 

Lets make the fractions into decimals. To make a fraction into decimal you have to divide the numerator by the denominator. The numerator is the top part of a fraction and the denominator is the bottom part of the fraction. 

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

Calculations

1/3
1 ÷ 3 =  0.3333.... 

5/6 
5 ÷ 6 = 0.83333...

0.83333... is greater then 0.3333.....
Therefore 5/6 is greater then 1/3 
1/3 is smaller then 5/6 
5 0
2 years ago
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