Answer:
300+90+9
-45=0+40+5
Step-by-step explanation:
399-45=354
Use a Mohr circle to find the maximum shear stress relative to the axial stress.
Here we assume the axial stress is sigma, the transverse axial stress is zero.
So we have a Mohr circle with (0,0) and (0,sigma) as a diameter.
The centre of the circle is therefore (0,sigma/2), and the radius is sigma/2.
From the circle, we determine that the maximum stress is the maximum y-axis values, namely +/- sigma/2, at locations (sigma/2, sigma/2), and (sigma/2, -sigma/2).
Given that the maximum shear stress is 60 MPa, we have
sigma/2=60 MPa, or sigma=120 MPa.
(note: 1 MPa = 1N/mm^2)
Therefore
100 kN/(pi*d^2/4)=100,000 N/(pi*d^2/4)=120 MPa where d is in mm.
Solve for d
d=sqrt(100,000*4/(120*pi))
=32.5735 mm
Answer:
C = (1, -1)
Step-by-step explanation:
For that 3:1 division, the calculated value of point B is ...
B = (3C +1A)/(3+1)
Solving for the value of C, we find ...
4B = 3C + A . . . . multiply by 4
4B -A = 3C . . . . . subtract A; next divide by 3.
C = (4B -A)/3 = ((4(-1)-(-7))/3, (4(0)+-3)/3) . . . . substitute given values
C = (3/3, -3/3) . . . . simplify a bit
C = (1, -1)
Answer: multiply and estimate
Step-by-step explanation:
