# Which triangle’s unknown side length measures 53sqrt units?

2 answers:

The answer is the one with 10 and 47 I just got it right

<span>Which triangle’s unknown side length measures 53 sqrt units?

</span><span>

assuming they are right triangles

we know that

c</span>²=a²+b²

case a) 6 and 91sqrt

c=√91

a=6

b=√53

so

a²+b²----> 6²+√53²----> 36+53----> 89

89 is not √91²

case b) <span>10 and 47sqrt

c=10</span>

a=√53

b=√47

a²+b²----> 53+47----> 100

100 is equal to 10²------> is ok

case c) <span>34sqrt and 19sqrt

c=</span>√53

a=√34

b=√19

a²+b²----> 34+19----> 53

53 is equal to √53²----> is ok

case d) <span>20 and 73sqrt

c=20

a=</span>√73

b=√53

a²+b²----> √73²+√53²----> 126

126 is not 20²

**the answers are**

**10 and 47sqrt**

**34sqrt and 19sqrt**

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1/4(6 + 2c) > 3

0.25 (6+ 2c) > 3

1.5 + 0.5c > 3

0.5c > 1.5

c > 3

Or multiply both sides by 4 to get rid of the 1/4,

6 + 2c > 12

2c > 6

c >3

**Answer:**

a. -30

b. -18

c. 4

d. -3

**Step-by-step explanation:**

it's 100% right

Answer:

Relationship is :linear

Rate of change : 3

Y-intercept : (0,1)

Equation that models the data : y=3x+1

Step-by-step explanation:

**Answer:**

160 because dat is so simple

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a.1 b.1/16 c.1/256 d.1 e.4/9 f.16/81