Which triangle’s unknown side length measures 53sqrt units?
2 answers:
The answer is the one with 10 and 47 I just got it right
<span>Which triangle’s unknown side length measures 53 sqrt units?
</span><span>
assuming they are right triangles
we know that
c</span>²=a²+b²
case a) 6 and 91sqrt
c=√91
a=6
b=√53
so
a²+b²----> 6²+√53²----> 36+53----> 89
89 is not √91²
case b) <span>10 and 47sqrt
c=10</span>
a=√53
b=√47
a²+b²----> 53+47----> 100
100 is equal to 10²------> is ok
case c) <span>34sqrt and 19sqrt
c=</span>√53
a=√34
b=√19
a²+b²----> 34+19----> 53
53 is equal to √53²----> is ok
case d) <span>20 and 73sqrt
c=20
a=</span>√73
b=√53
a²+b²----> √73²+√53²----> 126
126 is not 20²
the answers are
10 and 47sqrt
34sqrt and 19sqrt
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