Since the bases are the same, set the exponents equal to each other. X = 3
Answer:
The period is of
units.
The horizontal shift is of 30 units to the left.
Step-by-step explanation:
The secant function has the following general format:
![y = A\sec{(Bx + C)}](https://tex.z-dn.net/?f=y%20%3D%20A%5Csec%7B%28Bx%20%2B%20C%29%7D)
A represents the vertical shift.
C represents the horizontal shift. If C is positive, the shift is to the right. If it is negative, it is to the left.
The period is ![P = \frac{2\pi}{B}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B2%5Cpi%7D%7BB%7D)
In this question:
![y = 7\sec{6x - 30}](https://tex.z-dn.net/?f=y%20%3D%207%5Csec%7B6x%20-%2030%7D)
So ![B = 6, C = -30](https://tex.z-dn.net/?f=B%20%3D%206%2C%20C%20%3D%20-30)
Then ![P = \frac{2\pi}{6} = \frac{\pi}{3}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B2%5Cpi%7D%7B6%7D%20%3D%20%5Cfrac%7B%5Cpi%7D%7B3%7D)
The period is of
units.
The horizontal shift is of 30 units to the left.
Answer:
50 laps
Step-by-step explanation:
10 laps : 6 minutes
multiply both sides by 5
50 laps: 30 minutes
Answer:
dx/dt = 0,04 m/sec
Step-by-step explanation:
Area of the circle is:
A(c) =π*x² where x is a radius of the circle
Applying differentiation in relation to time we get:
dA(c)/dt = π*2*x* dx/dt
In this equation we know:
dA(c)/dt = 0,5 m²/sec
And are looking for dx/dt then
0,5 = 2*π*x*dx/dt when the area of the sheet is 12 m² (1)
When A(c) = 12 m² x = ??
A(c) = 12 = π*x² ⇒ 12 = 3.14* x² ⇒ 12/3.14 = x²
x² = 3,82 ⇒ x = √3,82 ⇒ x = 1,954 m
Finally plugging ths value in equation (1)
0,5 = 6,28*1,954*dx/dt
dx/dt = 0,5 /12.28
dx/dt = 0,04 m/sec
Answer:
It is not equal and I have no idea how to explain it