3 years ago

Subtract the fractions and simplify the answer 9-51/3 Can you show me

1 answer:

4 0

When adding or subtracting fractions the denominators must be the same convert 9 to 27/3 27/3-51/3= - 22/3 or - 7 1/3 nope this helps

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What is the slope of a line perpendicular to a line that's passes through (3,8) and (1,-4)?

Serjik [45]

Answer:

-1/6

Step-by-step explanation:

First find the slope of the line through the points

m = (y2-y1)/(x2-x1)

= (-4-8)/(1-3)

= -12/-2

Now we need to find the slope of the line that is perpendicular

Perpendicular lines multiply to -1

6 * mp = -1

mp = -1/6

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3 years ago

Solve the following equation. Remember to check for extraneous solutions 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

xxMikexx [17]

Answer:

-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, $\frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}$

⇒ $\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}$

⇒ $(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

⇒ $(x-2)(x-6) =0$ or, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

If, (x-2)(x-6) =0, then x=2 or x=6

If, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$ , then $x^{2} -5x-2=4$

and (x-6)(x+1) =0

Therefore, x=6 or -1

So the solutions for x are -1, 2 6. (Answer)

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3 years ago

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Veseljchak [2.6K]

Answer:

x=-3

Step-by-step explanation:

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Answer:

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1 year ago

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