<em>Note: Since you missed to mention the the expression of the function </em>
<em> . After a little research, I was able to find the complete question. So, I am assuming the expression as </em>
<em> and will solve the question based on this assumption expression of </em>
<em>, which anyways would solve your query.</em>
Answer:
As

Therefore,
is a root of the polynomial <em> </em>
As

Therefore,
is not a root of the polynomial <em> </em>
Step-by-step explanation:
As we know that for any polynomial let say<em> </em>
<em>, </em>
is the root of the polynomial if
.
In order to find which of the given values will be a root of the polynomial,
<em>, </em>we must have to evaluate <em> </em>
<em> </em>for each of these values to determine if the output of the function gets zero.
So,
Solving for 
<em> </em>










Thus,

Therefore,
is a root of the polynomial <em> </em>
<em>.</em>
Now, solving for 
<em> </em>







Thus,

Therefore,
is not a root of the polynomial <em> </em>
<em>.</em>
Keywords: polynomial, root
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