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2 years ago

9

70 toy cars 40% of the cars are blue

1 answer:

vaieri [72.5K]2 years ago

4 0

Answer:

28

Step-by-step explanation:

hope this helped!

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Help it is Parts of an Algebraic Expression

nlexa [21]

Answer:

terms- + -

variables- x p

coefficent-7 3

constant- 9

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The height of a volleyball, h, in feet, is given by h = −16t2 + 11t + 5.5, where t is the number of seconds after it has been hi

slavikrds [6]

Answer:

It will travel high enough

Step-by-step explanation:

Find the vertex of the parabola:

x=-b/2a

x=-11/2(-16)

x=-11/-32

x=11/32

Plug x=11/32 into quadratic to get the y-coordinate:

h=-16(11/32)^2+11(11/32)+5.5

h=7.391

Since 7.391>7.3, the volleyball will travel high enough (aka. yes)

3 0

2 years ago

Equation: -5 3/4- 3 1/2 Please help meh.

vampirchik [111]

Answer:

$-9\frac{1}{4}$

Step-by-step explanation:

$-5\frac{3}{4}-3\frac{1}{2}$

Step 1: Factor out the common term $-1$

$=-\left(5\frac{3}{4}+3\frac{1}{2}\right)$

Step 2: Add the whole numbers

$5 + 3 = 8$

Step 3: Combine the fractions:

$\frac{3}{4}+\frac{1}{2} = \frac{5}{4}\\\\=-\left(8+\frac{5}{4}\right)$

Step 4: Convert the improper fractions to mixed numbers

$\frac{5}{4} = 1\frac{1}{4}\\\\=-\left(8+1\frac{1}{4}\right)$

Step 5: Add the numbers

$8 + 1 =9 \\\\=-9\frac{1}{4}$

Therefore, the answer to the equation is $-9\frac{1}{4}$ in fraction, and decimal; $9.25$

4 0

2 years ago

Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).

bija089 [108]

<em>Note: Since you missed to mention the the expression of the function </em> $p(x)$ <em> . After a little research, I was able to find the complete question. So, I am assuming the expression as </em> $p(x)=x^4-9x^2-4x+12$ <em> and will solve the question based on this assumption expression of </em> $p(x)$ <em>, which anyways would solve your query.</em>

Answer:

As

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$

As

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say<em> </em> $p(x)$ <em>, </em> $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ <em>, </em>we must have to evaluate <em> </em> $p(x)$ <em> </em>for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$

<em> </em> $p(x)=x^4-9x^2-4x+12$

$p\left(-2\right)=\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12$

$\mathrm{Simplify\:}\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12:\quad 0$

$\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=\left(-2\right)^4-9\left(-2\right)^2+4\cdot \:2+12$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}$

$=2^4-2^2\cdot \:9+8+12$

$=2^4+20-2^2\cdot \:9$

$=16+20-36$

$=0$

Thus,

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$ <em>.</em>

Now, solving for $p\left(2\right)$

<em> </em> $p(x)=x^4-9x^2-4x+12$

$p\left(2\right)=\left(2\right)^4-9\left(2\right)^2-4\left(2\right)+12$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$p\left(2\right)=2^4-9\cdot \:2^2-4\cdot \:2+12$

$p\left(2\right)=2^4-2^2\cdot \:9-8+12$

$p\left(2\right)=2^4+4-2^2\cdot \:9$

$p\left(2\right)=16+4-36$

$p\left(2\right)=-16$

Thus,

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$ <em>.</em>

Keywords: polynomial, root

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7 0

2 years ago

Read 2 more answers

Please help its urgent

navik [9.2K]

Answer:

Step-by-step explanation:

18x-6=120

18x=120+6

18x=126

x=126÷18

x=7

5 0

2 years ago