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Natali [406]
3 years ago
6

What is the intersection of the given lines? AB←→ and EB←→

Mathematics
2 answers:
mariarad [96]3 years ago
7 0

Answer:

The intersection of the given line is B.

Step-by-step explanation:

In intersection two sets A and B, it is also represent as "A ∩ B". It contain only those elements that are common in sets. In this process two sets overlap each other.  

Given that:

Line AB and Line EB

Intersection ( ∩ )

AB ∩ EB

A∩E=(B)

OR

Suppose that

If A = {2, 4, 6, 8, 10} and B = {1, 3, 8, 4, 6}. Find intersection  

Solution:

A={2, 4, 6, 8, 10}

E = {1, 3, 8, 4, 6}

Intersection ( ∩ )

A ∩ E =({2, 4, 6, 8, 10}∩{1, 3, 8, 4, 6}).

A∩E={4,6,8}  //taking common value.

mezya [45]3 years ago
4 0

Answer:

point b

Step-by-step explanation:

did the topic

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Answer:

<h2><em>D = 3(75) + 30C</em></h2>

Step-by-step explanation:

If a school choir needs to make T Shirts for its 75 members and the printing company charges $3 per shirt, the total amount paid for shirts without coloured printing will be $3 * 75 = 3(75) ... 1

If the printing company charges $50 fee for each color to be printed on shirts, then the total number of colours on the short will cost $30C.... 2

where C is the total amount of colours on all the shirts.

The equation that will represents the relationship between the number of T-shirts orders, the number of colors on shirts and the total cost of the order will be gotten by taking the sum of equation 1 and 2.

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5 0
3 years ago
Chelsea took out three loans for a total of ​$ 78 comma 000 78,000 to start an organic orchard. Her​ business-equipment loan was
lianna [129]

Answer:

Business-equipment loan, A=$15000

Small-business loan, B=$24000

home-equity loan, C= $39000

Step-by-step explanation:

Let the Business-equipment loan at an interest rate of​ 11%=A

Let the​ small-business loan was at an interest rate of 5​% =B

Let her​ home-equity loan was at an interest rate of 4.5​%.=C

Since her total Loan=$78000

A+B+C=78000....(I)

Simple Interest = (P X R X T)/100

Since the Time, T=1 year

Interest on A = 0.11A

Interest on B = 0.05B

Interest on C = 0.045C

The total simple interest due on the loans in one year was ​$4605.

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The annual simple interest on the​ home-equity loan was ​$105 more than the interest on the​ business-equipment loan.

0.045C = 0.11A +105...(III)

We proceed to solve the simultaneous equations.

A+B+C=78000....(I)

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0.045C = 0.11A +105...(III)

From (III), 0.045C = 0.11A +105

Substitute 0.045C = 0.11A +105 into (II).

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0.22A+0.05B=4500

From (III),

C=\frac{22A}{9}+\frac{7000}{3}

Substitute into (I)

A+B+\frac{22A}{9}+\frac{7000}{3}=78000

\frac{31A}{9}+B=78000-\frac{7000}{3}

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31A+9B=681000 (Multiply by 0.05)

1.98A+0.45B=40500

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Subtracting

0.43A=6450

A=$15000

From (III)

C=\frac{22A}{9}+\frac{7000}{3}

C=\frac{22X15000}{9}+\frac{7000}{3} =39000

C=$39000

from (I)

A+B+C=78000

15000+B+39000=78000

B=$24000

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