Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
Let the missing term be X
Let the missing coefficient be Y
Therefore, (6a – X)5a = Y(a^2) – 35a
6a x 5a – X.5a = Y.a^2 – 35a
30a^2 – X.5a = Y.a^2 – 35a
Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
30 = Y; 5X = 35
Y = 30; X = 7
Therefore, (6a-7)5a = 30 a^2 – 35a
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Simple...
you have:
and
Now, the first one is easy just divide it...
Now....
needs to be converted...
Multiply the whole number*denominator...
4*8=32
Now add the numerator....
32+3=35
Now use the original denominator...
Now divide...
Thus, your answer.
Answer: 6
Explanation: calculator
Answer:
So about 95 percent of the observations lie between 480 and 520.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviations of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
The mean is 500 and the standard deviation is 10.
About 95 percent of the observations lie between what two values?
From the Empirical Rule, this is from 500 - 2*10 = 480 to 500 + 2*10 = 520.
So about 95 percent of the observations lie between 480 and 520.
Answer:
Step-by-step explanation: