Answer:
186.5 + 2x
Step-by-step explanation:
First, radify 25. Luckily it's a perfect square so it will be 5.
Second, divide within the parentheses. You're expression should look like this.
(93-5+x+42/8)2
Divide 42/8. The decimal form would be 5.25, while the fraction should be 5 1/4.
Third, solve within the parentheses from left to right. Right now you're expression should look like this:
(93-5+x+5.25)2
Add all like terms
93-5+5.25=93.25
Fourth, multiply. Right now the expression should look like this:
(93.25 + x) 2
186.5 + 2x
Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130

I think is c. If im incorrect tell me if you have another chance tell me or tell another
Corollary - It is a theorem in geometry that the angles opposite two congruent sides of a triangle are also congruent. So I’d say true
Answer:
1- solve for x
2- put it in the bottom left square
Step-by-step explanation: