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2 years ago

Hello guys I really need help is anyone available please and ty

Mathematics

1 answer:

NARA [144]2 years ago

8 0

I believe it’s the second option

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Factor x2 + 29x - 30.

marysya [2.9K]

Ok the w to your question is to cross multiply <span>216=9m m=24

</span>

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3 years ago

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Two similiar rectangles have corresponding sides in the ratio 10:3. What is the ratio of their areas

lianna [129]

Answer:

Step-by-step explanation:

The ratio of its areas is equal to

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

In this problem the scale factor is equal to the ratio 10:3

Let

z-------> the scale factor

z2=(10/3)2=100/9

7 0

3 years ago

Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.

LuckyWell [14K]

Step-by-step explanation:

Quadrilateral ABCD is inscribed in a circle.

Opposite angles of a Quadrilateral are Supplementary.

$\therefore \: \angle A + \angle C = 180° \\ \therefore \:(2x + 3) \degree+ (2x + 1) \degree = 180° \\ \therefore \: (4x + 4) \degree = 180° \\ \therefore \: (4x + 4) = 180 \\ \therefore \: 4x = 180 - 4 \\ \therefore \: 4x = 176 \\ \therefore \: x = \frac{176}{4} \\ \therefore \: x = 44 \\ \\ m\angle A = (2x + 3) \degree \\ = (2 \times 44 + 3) \degree \\ = (88 + 3) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle A =91 \degree}} \\ \\ m\angle C = (2x + 1) \degree \\ = (2 \times 44 + 1) \degree \\ = (88 + 1) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle C=89\degree}} \\ \\ m\angle D= (x - 10) \degree \\ = (44 - 10) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle D =34\degree}} \\ \\ similarly \\ \\ \huge \red{ \boxed{ \therefore \: m\angle B = 146\degree}} \\ \\$

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3 years ago

In the right triangle shown

pav-90 [236]

Answer:

Step-by-step explanation:

Using the 30-60-90 triangle formula side AB would be double of side CB.

3 0

3 years ago

Find each measure cause i don't understand?

vekshin1

Answer:

x=6 . m<PQS=82 m<SQR=61 :)

Step-by-step explanation:

(13x+4) + (10x-1) = 141

combine like terms

23x+3=141

subtract 3 from both sides

23x=138

divide both sides by 23

x=6

substitute x into both original equations

m<PQS=13(6)+4

m<PQS=78+4

m<PQS= 82

m<SQR=10(6)+1

m<SQR=60+1

M<SQR=61

4 0

3 years ago

Read 2 more answers