Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
(x,y)
sub given points and see if true
A, (0,-13)
x=0
y=-13
3(-13)=5(0)-13
-39=0-13
-39=-13
false (other user was just guessing)
B. (3,1)
x=3,
y=1
3(1)=5(3)-13
3=15-13
3=2
false
C. (7,7)
x=7
y=7
3(7)=5(7)-13
21=35-13
21=22
false
D. (-6,-1)
3(-1)=5(-6)-13
-3=-30-13
-3=-43
false
answer is none of them
Answer:
Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.
Step-by-step explanation:
Given:
Let,
point S( x₁ , y₁) ≡ ( -1 , 1)
point T( x₂ , y₂) ≡ (3 , -5)
Point M( x , y ) is the Mid point of segment ST.
To Find:
Point M( x , y )= ?
Solution:
As Point M( x , y ) is the Mid point of segment ST.
So we have Mid Point Formula as
On substituting the given values in above equation we get
Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.
If Jamerra pays $450 simple interest in 2 years,
she will pay (450/2) = $225 simple interest each year.
225 / 3000 = 0.075 = 7.5 %
